Category: Coordinate Geometry

Question Number 151196 by peter frank last updated on 18/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 151164 by puissant last updated on 18/Aug/21 Commented by puissant last updated on 18/Aug/21 $${solve}\:{in}\:\mathbb{R} \\ $$ Answered by MJS_new last updated on…

Question Number 19884 by ajfour last updated on 17/Aug/17 Commented by ajfour last updated on 17/Aug/17 $$\:\:{A}\left({x}_{\mathrm{1}} ,{y}_{\mathrm{1}} \right)\:;\:\:{B}\left({x}_{\mathrm{2}} ,{y}_{\mathrm{2}} \right)\:\:;\:{C}\left({x}_{\mathrm{3}} ,{y}_{\mathrm{3}} \right)\:\:; \\ $$$$\:\:{D}\left({x}_{\mathrm{4}}…

Question Number 150864 by puissant last updated on 16/Aug/21 Answered by ajfour last updated on 16/Aug/21 $$\mathrm{70}°=\theta,\:\mathrm{30}°=\alpha,\:\mathrm{40}°=\beta,\:\mathrm{6}{cm}={r} \\ $$$${A}_{\mathrm{1}} =\left({r}−\mathrm{2}{r}\mathrm{cos}\:\theta\right){r}\mathrm{sin}\:\beta \\ $$$${A}_{\mathrm{2}} =\frac{{r}\left(\mathrm{1}−\mathrm{2cos}\:\theta\right)\left\{{r}\mathrm{sin}\:\theta−{r}\mathrm{sin}\:\beta\right\}}{\mathrm{2}} \\ $$$${A}_{\mathrm{3}}…

Question Number 150801 by puissant last updated on 15/Aug/21 Commented by puissant last updated on 15/Aug/21 $${find}\:{tan}\theta\:{please}.. \\ $$ Commented by mr W last updated…