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Category: Coordinate Geometry

Question-151899

Question Number 151899 by liberty last updated on 24/Aug/21 Answered by john_santu last updated on 24/Aug/21 $$\mathrm{A}=\int_{\mathrm{0}} ^{\mathrm{6}} \left(\frac{−\mathrm{x}^{\mathrm{3}} }{\mathrm{6}}+\mathrm{x}^{\mathrm{2}} \right)\mathrm{dx}=\left[−\frac{\mathrm{x}^{\mathrm{4}} }{\mathrm{24}}+\frac{\mathrm{x}^{\mathrm{3}} }{\mathrm{3}}\right]_{\mathrm{0}} ^{\mathrm{6}} \

Question-86063

Question Number 86063 by john santu last updated on 26/Mar/20 Answered by mr W last updated on 26/Mar/20 $$\left(\frac{\mathrm{1}}{{R}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{6}}−\frac{\mathrm{1}}{\mathrm{9}}\right)^{\mathrm{2}} =\mathrm{2}\left(\frac{\mathrm{1}}{{R}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{6}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{9}^{\mathrm{2}} }\right) \