Question Number 78453 by mathocean1 last updated on 17/Jan/20 $$\mathrm{ABC}\:\mathrm{is}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{points} \\ $$$$\mathrm{A}\left(−\mathrm{5};−\mathrm{5}\right)\:\mathrm{B}\left(−\mathrm{5};\mathrm{10}\right)\:\mathrm{C}\left(\mathrm{15};−\mathrm{5}\right). \\ $$$$\mathrm{the}\:\mathrm{cartesian}\:\mathrm{equtions}\:\mathrm{of}\:\left(\mathrm{AB}\right);\:\left(\mathrm{AC}\right) \\ $$$$\mathrm{and}\:\left(\mathrm{BC}\right)\:\mathrm{are}\:\mathrm{respectively} \\ $$$$\mathrm{x}=−\mathrm{5} \\ $$$$\mathrm{y}=−\mathrm{5} \\ $$$$\mathrm{x}+\mathrm{y}=\mathrm{5} \\ $$$$ \\…
Question Number 12902 by tawa last updated on 06/May/17 Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 06/May/17 $$\left.\mathrm{1}\right)\:\boldsymbol{{c}}=\mathrm{0}\:\:\:\:\:\:\:\left(\boldsymbol{{x}}=\mathrm{0}\Rightarrow\boldsymbol{{y}}=\mathrm{0}\right) \\ $$$$\boldsymbol{{y}}^{'} =\mathrm{2}\boldsymbol{{ax}}+\boldsymbol{{b}}\:\Downarrow \\ $$$$\left.\mathrm{2}\right)\begin{cases}{\mathrm{2}\boldsymbol{{a}}+\boldsymbol{{b}}=\mathrm{4}}\\{\mathrm{4}\boldsymbol{{a}}+\boldsymbol{{b}}=\mathrm{5}}\end{cases}\Rightarrow\mathrm{2}\boldsymbol{{a}}=\mathrm{1}\Rightarrow\boldsymbol{{a}}=\frac{\mathrm{1}}{\mathrm{2}},\boldsymbol{{b}}=\mathrm{3} \\ $$$$\boldsymbol{{y}}=\frac{\mathrm{1}}{\mathrm{2}}\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{3}\boldsymbol{{x}}\:\:\:.\:\blacksquare…
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Question Number 143890 by pandu last updated on 19/Jun/21 $${if}\:{a}+{b}+{c}=\pi\:\:\: \\ $$$$\:{tanA}+{tanB}+{tanC}\:={tanA}.{tanB}.{tanC} \\ $$$$\mathrm{FAILED}\:\mathrm{TO}\:\mathrm{CALCULATE} \\ $$ Answered by justtry last updated on 19/Jun/21 Answered by…
Question Number 78330 by john santu last updated on 16/Jan/20 $${given}\:{the}\:{regular}\:{pyramid} \\ $$$${T}.{ABCD}\:{with}\:{a}\:{square}\:{base} \\ $$$$.\:{length}\:{AB}\:=\:\mathrm{8}\:,\:{TC}\:=\:\mathrm{6}.\:{point} \\ $$$${P}\:{is}\:{mid}\:{BC}.\:{if}\:{x}\:{is}\:{the}\:{angle}\: \\ $$$${between}\:{TP}\:{and}\:{BD}.\:{determine} \\ $$$${the}\:{value}\:{of}\:\mathrm{cos}\:{x}. \\ $$ Terms of…
Question Number 143718 by cherokeesay last updated on 17/Jun/21 Commented by TheHoneyCat last updated on 17/Jun/21 $${Hi},\:{what}\:{do}\:{you}\:{mean}\:{by}\:''\mid{B}\mid''? \\ $$$${it}\:{looks}\:{like}\:{you}\:{are}\:{talking}\:{about}\:{a}\:{norm}\:{but}\:{which}\:{one}? \\ $$ Commented by TheHoneyCat last…
Question Number 78119 by jagoll last updated on 14/Jan/20 $${find}\:{the}\:{center}\:{point}\:{ellips} \\ $$$$\mathrm{5}{x}^{\mathrm{2}} +\mathrm{8}{y}^{\mathrm{2}} −\mathrm{24}{x}−\mathrm{24}{y}+\mathrm{4}{xy}=\mathrm{0} \\ $$ Commented by jagoll last updated on 14/Jan/20 $${this}\:{problem}\:{is}\:{right}\:{or}\:{not}? \\…
Question Number 12576 by tawa last updated on 26/Apr/17 $$\mathrm{Given}\:\mathrm{two}\:\mathrm{functions}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{and}\:\mathrm{g}\left(\mathrm{x}\right)\:\mathrm{with}\:\mathrm{f}\left(\mathrm{1}\right)\:=\:\mathrm{7},\:\mathrm{g}\left(\mathrm{2}\right)\:=\:\mathrm{1}\:,\:\mathrm{f}'\left(\mathrm{1}\right)\:=\:\mathrm{204} \\ $$$$\mathrm{and}\:\mathrm{g}'\left(\mathrm{x}\right)\:=\:\mathrm{22}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{derivative}\:\mathrm{of}\:\:\mathrm{f}\left(\mathrm{g}\left(\mathrm{x}\right)\right)\:\mathrm{at}\:\mathrm{x}\:=\:\mathrm{2} \\ $$ Answered by mrW1 last updated on 26/Apr/17 $$\frac{{df}}{{dx}}=\frac{{df}\left({g}\right)}{{dg}}×\frac{{dg}\left({x}\right)}{{dx}}={f}'\left({g}\left({x}\right)\right)×{g}'\left({x}\right) \\ $$$$={f}'\left({g}\left(\mathrm{2}\right)\right)×{g}'\left(\mathrm{2}\right)={f}'\left(\mathrm{1}\right)×{g}'\left(\mathrm{2}\right)=\mathrm{204}×\mathrm{22} \\…
Question Number 77854 by jagoll last updated on 11/Jan/20 $${a}\:{circle}\: \\ $$$${offends}\:{the}\:{y}\:{axis}\:{at}\:{point}\left(\mathrm{0},{b}\right)\: \\ $$$${and}\:{through}\:{the}\:{intersection} \\ $$$${of}\:{the}\:{curve}\:{y}\:=\:{x}\:−\mathrm{2}\sqrt{{x}}+\frac{\mathrm{1}}{\mathrm{4}}.\: \\ $$$${value}\:{of}\:{b}\:=\:? \\ $$ Commented by john santu last…
Question Number 12246 by tawa last updated on 16/Apr/17 $$\mathrm{Let}\:\:\mathrm{g}\left(\mathrm{x}\right)\:\mathrm{be}\:\mathrm{an}\:\mathrm{ininitely}\:\mathrm{differentiable}\:\mathrm{function}\:,\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{g}\left(\mathrm{2x}\:+\:\mathrm{6}\right)\:=\:\mathrm{g}^{'} \left(\mathrm{3x}\:−\:\mathrm{1}\right)\:\mathrm{for}\:\mathrm{all}\:\mathrm{x}. \\ $$$$\mathrm{given}\:\mathrm{that}\:\:\mathrm{g}\left(\frac{\mathrm{44}}{\mathrm{3}}\right)\:=\:\mathrm{33}\:.\:\:\mathrm{find}\:\:\:\mathrm{g}''\left(\mathrm{8}\right) \\ $$ Answered by mrW1 last updated on 16/Apr/17 $${u}=\mathrm{3}{x}−\mathrm{1}\Rightarrow{x}=\frac{{u}+\mathrm{1}}{\mathrm{3}}\Rightarrow\mathrm{2}{x}+\mathrm{6}=\mathrm{2}×\frac{{u}+\mathrm{1}}{\mathrm{3}}+\mathrm{6}=\frac{\mathrm{2}{u}+\mathrm{20}}{\mathrm{3}}…