Coordinate Geometry – Page 81

show-that-every-sphere-through-the-circle-x-2-y-2-2ax-r-2-0-z-0-z-0-cuts-orthogonally-every-sphere-through-the-circle-x-2-z-2-r-2-y-o-

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Question Number 8756 by trapti rathaur@ gmail.com last updated on 25/Oct/16 $s h o w t h a t e v e r y s p h e r e t h r o u g h t h e c i r c l e x^{2} + y^{2} - 2 a x + r^{2} = 0, z = 0$ $, z = 0 c u t s o r t h o g o n a l l y e v e r y s p h e r e t h r o u g h t h e c i r c l e$ $x^{2} + z^{2} = r^{2}, y = o .$ Terms…

find-the-equation-of-the-sphere-which-touches-the-plane-3x-2y-z-2-0-at-the-point-1-2-1-and-cuts-orthogonally-the-the-sphere-x-2-y-2-z-2-4x-6y-4-0-

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Question Number 8755 by trapti rathaur@ gmail.com last updated on 25/Oct/16 $f i n d t h e e q u a t i o n o f t h e s p h e r e w h i c h t o u c h e s t h e p l a n e$ $3 x + 2 y - z + 2 = 0 a t t h e p o i n t (1, - 2, 1) a n d c u t s o r t h o g o n a l l y t h e$ $t h e s p h e r e x^{2} + y^{2} + z^{2} - 4 x + 6 y + 4 = 0$ Terms of Service Privacy…

Let-consider-I-R-2-a-parametric-curve-defined-as-t-I-t-t-2-1-t-3-1-2t-t-3-1-Prove-that-for-a-b-c-I-a-b-c-are-on-the-same-lign-iff-abc-a-b-c-1-

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Question Number 74280 by ~blr237~ last updated on 21/Nov/19 $L e t c o n s i d e r α : I \to R^{2} a p a r a m e t r i c c u r v e d e f i n e d a s$ $\forall t \in I α (t) = (\frac{t^{2} - 1}{t^{3} - 1}, \frac{2 t}{t^{3} - 1})$ $P r o v e t h a t f o r a, b, c \in I$ $α (a), α (b), α (c) a r e o n t h e s a m e l i g n i f f a b c = a + b + c + 1$ Commented by MJS…

if-any-angle-of-equilateral-triangle-is-1-2-and-any-one-side-is-x-3y-5-0-then-equation-of-the-other-two-sides-are-

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Question Number 8608 by tawakalitu last updated on 17/Oct/16 $if any angle of equilateral triangle is$ $(- 1, 2) and any one side is x - \sqrt{3 y} + 5 = 0$ $then equation of the other two sides are ? ?$ Answered by sandy_suhendra last updated on 18/Oct/16 Answered by…

Question-73919

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Question Number 73919 by necxxx last updated on 16/Nov/19 Commented by necxxx last updated on 16/Nov/19 $G o o d d a y s i r s . T h i s q u e s t i o n w a s f o r m e d$ $a n d s o l v e d b y s o m e o f u s h e r e . I r e a l l y$ $d o n o t r e m e m b e r t h e q u e s t i o n o r$ $a p p r o a c h e s a p p l i e d . P l e a s e h e l p .$ $${Thanks}\:{in}\:{advance}.…

C-n-2-1-8-P-n-8-find-n-

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Question Number 139422 by 676597498 last updated on 26/Apr/21 $C_{n}^{2} = \frac{1}{8} P_{n}^{8}$ $f i n d n$ Commented by mohammad17 last updated on 27/Apr/21 $${can}\:{not}\:{find}\:{value}\:{of}\:{n}\:{in}\:{this}\:{form}…

Find-the-equation-of-the-perpendicular-bisector-of-the-line-joining-the-points-5-4-to-the-point-9-3-

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Question Number 8243 by lepan last updated on 04/Oct/16 $F i n d t h e e q u a t i o n o f t h e p e r p e n d i c u l a r b i s e c t o r o f t h e l i n e j o i n i n g t h e p o i n t s (- 5, 4) t o t h e p o i n t (9, - 3)$ Answered by sandy_suhendra last updated on 04/Oct/16 $let A (- 5, 4) and B (9, - 3)$ $$\mathrm{P}\:\mathrm{is}\:\mathrm{midpoint}\:\mathrm{of}\:\mathrm{AB}\:\mathrm{so}\:\mathrm{P}\left(\frac{−\mathrm{5}+\mathrm{9}}{\mathrm{2}}\:,\:\frac{\mathrm{4}−\mathrm{3}}{\mathrm{2}}\:\right)=\mathrm{P}\left(\mathrm{2},\frac{\mathrm{1}}{\mathrm{2}}\right) \…

show-that-the-plane-x-2y-3z-d-0-is-perpendiculr-to-each-of-the-plane-is-2x-5y-4z-1-0-and-4x-7y-3z-2-0-

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Question Number 8150 by trapti rathaur@ gmail.com last updated on 02/Oct/16 $s h o w t h a t t h e p l a n e x + 2 y - 3 z + d = 0 i s p e r p e n d i c u l r t o e a c h o f$ $t h e p l a n e i s 2 x + 5 y + 4 z + 1 = 0 a n d 4 x + 7 y + 3 z + 2 = 0 .$ Commented by 123456 last updated on 03/Oct/16 $$\alpha:{x}+\mathrm{2}{y}−\mathrm{3}{z}+{d}=\mathrm{0} \…

Question-73671

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Question Number 73671 by Tanmay chaudhury last updated on 14/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-139106

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Question Number 139106 by mr W last updated on 23/Apr/21 Commented by mr W last updated on 25/Apr/21 $a n u n i f o r m d e n s e r o p e w i t h l e n g t h L$ $a n d m a s s m i s p u l l e d b y a t r u c k w i t h$ $c o n s t a n t s p e e d . o n t h e e n d o f r o p e a$ $${mass}\:\boldsymbol{{M}}\:{is}\:{connected}.\:{if}\:{the}\:{friction}…

Category: Coordinate Geometry