Category: Differential Equation

Question Number 120905 by bemath last updated on 03/Nov/20 $${\mathrm{y}}^{\prime }={\mathrm{xy}}^2-\frac{\mathrm{y}}{\mathrm{x}}$$ Answered by Bird last updated on 03/Nov/20 $$\Rightarrow\frac{{y}^{'} }{{y}^{\mathrm{2}} }={x}−\frac{\mathrm{1}}{{yx}}\:{let}\:\frac{\mathrm{1}}{{y}}={z}\:\Rightarrow{z}^{'} =−\frac{{y}^{'} }{{y}^{\mathrm{2}}…

Question Number 120811 by fajri last updated on 03/Nov/20 $$Findthesingularpointinthe$$$$differentialequation:$$$$$$$$(x^3-x^2-9x+9)\frac{d^{2}y}{{dx}^2}+2x\frac{dy}{dx}+(x-3)y=0$$ Answered by 675480065…

Question Number 120595 by fajri last updated on 01/Nov/20 $$$$$$SolutionfromDifferentialEquationSystem:$$$$$$$$\left\{_{{x}_{\mathrm{2}} ^{'} \:=\:\:\mathrm{2}{x}_{\mathrm{1}} \:−\:\mathrm{3}{x}_{\mathrm{2}} \:\:,\:{x}_{\mathrm{2}} \:\left(\mathrm{0}\right)\:=\:−\mathrm{1}} ^{{x}_{\mathrm{1}} ^{'} \:=\:\mathrm{2}{x}_{\mathrm{1}} −\:\mathrm{2}{x}_{\mathrm{2}}…

Question Number 54663 by Mikael_Marshall last updated on 08/Feb/19 $$y=cos2t\times sen2t$$$$$$$$y^{\prime }=?$$ Commented by maxmathsup by imad last updated on 08/Feb/19…

Question Number 119933 by bramlexs22 last updated on 28/Oct/20 $$\frac{dx}{dy}-y={xy}^2$$ Answered by bobhans last updated on 28/Oct/20 $$\frac{dy}{dx}=\frac{1}{y+{xy}^2}=\frac{\frac{1}{y^2}}{\frac{1}{y}+x}$$$${let}\:\frac{\mathrm{1}}{{y}}=\:{u}\:\Rightarrow\frac{{du}}{{dx}}\:=\:−\frac{\mathrm{1}}{{y}^{\mathrm{2}} }\:\frac{{dy}}{{dx}}…