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Category: Differential Equation

3x-5y-dx-x-y-dy-0-

Question Number 118975 by benjo_mathlover last updated on 21/Oct/20 (3x5y)dx+(x+y)dy=0 Answered by 1549442205PVT last updated on 21/Oct/20 (3x5y)dx+(x+y)dy=0(1)Puty=xtdy=xdt+tdx$$\left(\mathrm{1}\right)\Leftrightarrow\left(\mathrm{3x}−\mathrm{5xt}\right)\mathrm{dx}+\left(\mathrm{x}+\mathrm{xt}\right)\left(\mathrm{xdt}+\mathrm{tdx}\right) \