Question Number 113243 by ShakaLaka last updated on 11/Sep/20 Commented by ShakaLaka last updated on 11/Sep/20 $$\mathrm{Can}\:\mathrm{anybody}\:\mathrm{solve}\:\mathrm{this} \\ $$$$\mathrm{question}? \\ $$ Commented by mr W…
Question Number 47624 by Umar last updated on 12/Nov/18 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{d}.\mathrm{e}\:\mathrm{using}\:\mathrm{method}\:\mathrm{of}\:\mathrm{variation} \\ $$$$\mathrm{of}\:\mathrm{parameter}. \\ $$$$ \\ $$$$\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }+\mathrm{3}\frac{\mathrm{dy}}{\mathrm{dx}}+\mathrm{2y}=\mathrm{sin}\left(\mathrm{e}^{\mathrm{x}} \right) \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 47623 by Umar last updated on 12/Nov/18 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{d}.\mathrm{e}\:\mathrm{using}\:\mathrm{method}\:\mathrm{of}\:\mathrm{variation} \\ $$$$\mathrm{of}\:\mathrm{parameter}. \\ $$$$ \\ $$$$\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }+\mathrm{3}\frac{\mathrm{dy}}{\mathrm{dx}}+\mathrm{2y}=\mathrm{sin}\left(\mathrm{e}^{\mathrm{x}} \right) \\ $$ Terms of Service Privacy…
Question Number 113060 by bemath last updated on 12/Sep/20 $$\:\left(\mathrm{1}\right)\:\sqrt{\frac{\mathrm{dy}}{\mathrm{dx}}}\:=\:\frac{\mathrm{d}\left(\sqrt{\mathrm{y}}\right)}{\mathrm{dx}} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{x}^{\mathrm{2}} \:\equiv\:\mathrm{73}\:\left(\mathrm{mod}\:\mathrm{216}\right) \\ $$$$\left(\mathrm{3}\right)\:\mathrm{If}\:\mathrm{2}^{\mathrm{x}_{\mathrm{1}} } +\mathrm{2}^{\mathrm{x}_{\mathrm{2}} } +\mathrm{2}^{\mathrm{x}_{\mathrm{3}} } +…+\mathrm{2}^{\mathrm{x}_{\mathrm{n}} } =\mathrm{80},\mathrm{000} \\ $$$$\:\mathrm{where}\:\mathrm{x}_{\mathrm{1}}…
Question Number 47510 by Rio Michael last updated on 11/Nov/18 $${the}\:{curve}\:{y}\:=\:\mathrm{3}{x}^{\mathrm{2}} \:+\mathrm{4}\:\left({x}=\mathrm{2}\:{and}\:{x}=\mathrm{3}\right)\:{is}\:{rotated}\:{about}\:{the}\: \\ $$$${x}.{axis}.{find}\:{the}\:{volume}\:{of}\:{the}\:{solid}\:{generated}.{Leave}\:{your} \\ $$$${answer}\:{in}\:{terms}\:{of}\:\pi. \\ $$ Commented by mr W last updated on…
Question Number 112844 by bemath last updated on 10/Sep/20 $$\:\mathrm{Find}\:\mathrm{general}\:\mathrm{solution} \\ $$$$\left(\mathrm{1}\right)\left(\frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{1}+\mathrm{y}}\right)\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{cos}\:\mathrm{x} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{X}\:=\:\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{2}}{\mathrm{11}}\right)+\mathrm{cot}^{−\mathrm{1}} \left(\frac{\mathrm{24}}{\mathrm{7}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{3}}\right) \\ $$$$\:\:\mathrm{find}\:\mathrm{X}\:. \\ $$ Commented by bemath last…
Question Number 112840 by bemath last updated on 10/Sep/20 $$\mathrm{solve}\:\mathrm{y}''−\mathrm{y}'+\mathrm{e}^{\mathrm{2x}} \mathrm{y}\:=\:\mathrm{0} \\ $$ Answered by john santu last updated on 10/Sep/20 $$\:{solve}\:{y}''−{y}'\:+{e}^{\mathrm{2}{x}} \:{y}\:=\:\mathrm{0}. \\ $$$$\:{substitute}\:{u}\:=\:{e}^{{x}}…
Question Number 46972 by 23kpratik last updated on 03/Nov/18 $$\boldsymbol{{let}}\:{m},{n}\:{denote}\:{any}\:{two}\:{possitive}\:{relative}\:{prime}\:{integers},{then}\:{prove}\:{that}\phi\left({mn}\right)=\phi\left({m}\right)\centerdot\phi\left({n}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 112456 by bobhans last updated on 08/Sep/20 $$\mathrm{solve}\:\frac{\mathrm{dy}}{\mathrm{dx}}−\frac{\mathrm{4y}}{\mathrm{x}}\:=\:\mathrm{1}+\frac{\mathrm{2}}{\mathrm{x}} \\ $$ Answered by john santu last updated on 08/Sep/20 $${let}\:{u}\:=\:{yx}^{−\mathrm{4}} \:\rightarrow\frac{{du}}{{dx}}\:=\:−\mathrm{4}{yx}^{−\mathrm{5}} +{x}^{−\mathrm{4}} \:\frac{{dy}}{{dx}} \\…
Question Number 46694 by MJS last updated on 30/Oct/18 $$\left({y}''{y}−\left({y}'\right)^{\mathrm{2}} \right)\mathrm{e}^{\frac{{y}'}{{y}}} ={y}^{\mathrm{2}} \\ $$$$\mathrm{not}\:\mathrm{sure}\:\mathrm{if}\:\mathrm{it}'\mathrm{s}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{this}\:\mathrm{at}\:\mathrm{all}… \\ $$ Answered by ajfour last updated on 30/Oct/18 $$\mathrm{ln}\:\left[{y}''{y}−\left({y}'\right)^{\mathrm{2}} \right]+\frac{{y}'}{{y}}=\mathrm{2ln}\:{y}…