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Question Number 199996 by jlewis last updated on 12/Nov/23 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{first}\:\mathrm{order}\:\mathrm{energy}\:\mathrm{correction}\:\mathrm{for} \\ $$$$\mathrm{1}−\mathrm{dimensional}\:\mathrm{non}−\mathrm{degenerate}\:\mathrm{anharmonic} \\ $$$$\mathrm{oscillator}\:\mathrm{whose}\:\mathrm{harmiltonian}\:\mathrm{is}\:\mathscr{H}\underline{\mathscr{L}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 200022 by jlewis last updated on 12/Nov/23 $$\mathrm{solve}\:\mathrm{the}\:\mathrm{associated}\:\mathrm{legendre}\:\mathrm{equation} \\ $$$$\lambda={l}\:\left({l}+\mathrm{1}\right)\eta^{\mathrm{2}} \:;{l}=\mathrm{0},\mathrm{1},\mathrm{2}…\:\:\:{and}\:{m}^{\mathrm{2}} \leqslant\:{l}\left({l}+\mathrm{1}\right)\: \\ $$$${which}\:{requires}\:−{l}\leqslant{m}\leqslant{l}\:\mathrm{using}\:\mathrm{power}\:\mathrm{series} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 199844 by jlewis last updated on 10/Nov/23 $$\mathrm{solve}\:\frac{\mathrm{d}^{\mathrm{2}} }{\mathrm{dx}^{\mathrm{2}} }\:\mathrm{x} \\ $$ Answered by AST last updated on 10/Nov/23 $$\frac{{d}}{{dx}}\left(\frac{{d}}{{dx}}{x}\right)=\frac{{d}}{{dx}}\left(\mathrm{1}\right)=\mathrm{0} \\ $$ Answered…
Question Number 199891 by Mathspace last updated on 10/Nov/23 $${solve}\:{by}\:{laplce}\:{transform} \\ $$$${y}^{''} −{y}^{'} +{y}\:=\left({x}+\mathrm{1}\right){e}^{{x}} \\ $$ Commented by Mathspace last updated on 10/Nov/23 $${with}\:{y}\left(\mathrm{0}\right)=\mathrm{1}\:{and}\:{y}^{'} \left(\mathrm{0}\right)=−\mathrm{1}…
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Question Number 198646 by Engr_Jidda last updated on 22/Oct/23 Answered by mr W last updated on 23/Oct/23 $${story}\:{is}\:{silly},\:{but}\:{solution}\:{is}\:{easy}! \\ $$$$ \\ $$$${girl}:\:{a}\left({t}\right)=\mathrm{1}×{t}={t} \\ $$$${boy}:\:\:{b}\left({t}\right)=\mathrm{5}×{t}=\mathrm{5}{t} \\…
Question Number 198285 by samiksha last updated on 16/Oct/23 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198286 by samiksha last updated on 16/Oct/23 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198104 by sonu753 last updated on 10/Oct/23 Answered by mr W last updated on 11/Oct/23 $$\frac{{dx}}{{dy}}−\frac{{x}}{{y}}=−{y} \\ $$$$\left[{d}.{e}.\:{of}\:{type}\:{y}'+{p}\left({x}\right){y}={q}\left({x}\right)\right] \\ $$$$\int{p}\left({y}\right){dy}=−\int\frac{{dy}}{{y}}=−\mathrm{ln}\:{y} \\ $$$${u}\left({y}\right)={e}^{−\mathrm{ln}\:{y}} =\frac{\mathrm{1}}{{y}}…