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Category: Differential Equation

solve-d-2-y-dx-2-2x-dy-dx-5y-0-

Question Number 38876 by tawa tawa last updated on 30/Jun/18 $$\mathrm{solve}:\:\:\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\:\:+\:\:\mathrm{2x}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:\:+\:\mathrm{5y}\:=\:\mathrm{0} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18 $${it}\:{is}\:{realy}\:{very}\:{good}\:{problem}…{in}\:{search}..{and} \\ $$$${finding}\:{way}\:{to}\:{solve}\:{it}……

x-y-1-dy-dx-1-

Question Number 104357 by bemath last updated on 21/Jul/20 $$\left({x}+{y}+\mathrm{1}\right)\:\frac{{dy}}{{dx}}\:=\:\mathrm{1}\: \\ $$ Answered by john santu last updated on 21/Jul/20 $${let}\:{z}\:=\:{x}+{y}+\mathrm{1} \\ $$$$\frac{{dz}}{{dx}}\:=\:\mathrm{1}+\:\frac{{dy}}{{dx}}\:\Rightarrow\frac{{dy}}{{dx}}\:=\:\frac{{dz}}{{dx}}−\mathrm{1} \\ $$$$\left(\rightarrow\right)\:{z}.\left(\frac{{dz}}{{dx}}−\mathrm{1}\right)\:=\:\mathrm{1}\:…

dy-dx-2x-y-1-x-4y-3-

Question Number 169558 by greougoury555 last updated on 03/May/22 $$\:\:\:\:\:\:\:\frac{{dy}}{{dx}}\:=\:\frac{\mathrm{2}{x}−{y}+\mathrm{1}}{{x}−\mathrm{4}{y}+\mathrm{3}}\:\:\: \\ $$ Answered by ali009 last updated on 03/May/22 $${a}\mathrm{1}=\mathrm{2}\:\:{a}\mathrm{2}=\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{a}\mathrm{1}/{a}\mathrm{2}=\mathrm{2} \\ $$$${b}\mathrm{1}=−\mathrm{1}\:\:{b}\mathrm{2}=−\mathrm{4}\:\:\:\:\:\:\:\:\:\:\:\:{b}\mathrm{1}/{b}\mathrm{2}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$$${so} \\…