Question Number 93900 by i jagooll last updated on 16/May/20 $$\mathrm{y}''+\mathrm{2}{xy}=\:\mathrm{y} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 93828 by i jagooll last updated on 15/May/20 $$\mathrm{sin}\:\mathrm{x}\:\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)−\mathrm{y}\:=\:\mathrm{2sin}\:\mathrm{x}\: \\ $$ Commented by i jagooll last updated on 15/May/20 Commented by mathmax by…
Question Number 93818 by i jagooll last updated on 15/May/20 $$\left(\mathrm{y}−\mathrm{xy}^{\mathrm{2}} \right)\mathrm{dx}\:+\left(\mathrm{x}+\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} \right)\mathrm{dy}\:=\:\mathrm{0} \\ $$ Answered by i jagooll last updated on 15/May/20 $$\mathrm{ydx}+\mathrm{xdy}=\mathrm{xy}^{\mathrm{2}}…
Question Number 28280 by Cheyboy last updated on 23/Jan/18 $${Find}\:{dy}/{dx} \\ $$$${x}^{\frac{\mathrm{2}}{\mathrm{3}}} \left(\mathrm{6}−{x}\right)^{\frac{\mathrm{1}}{\mathrm{3}\:}} \:{to}\:{it}\:{simplest}\:{form} \\ $$ Commented by abdo imad last updated on 23/Jan/18 $${we}\:{have}\:{y}\left({x}\right)=\left({x}^{\mathrm{2}}…
Question Number 93815 by i jagooll last updated on 15/May/20 $$\left(\mathrm{D}^{\mathrm{2}} +\mathrm{6D}+\mathrm{9}\right)\mathrm{y}\:=\:\frac{\mathrm{e}^{−\mathrm{3x}} }{\mathrm{x}^{\mathrm{3}} }\: \\ $$ Answered by john santu last updated on 15/May/20 $$\mathrm{homogenous}\:\mathrm{solution}…
Question Number 159346 by Ar Brandon last updated on 15/Nov/21 $${xy}''+\mathrm{2}\left({x}+\mathrm{1}\right){y}'+\left({x}+\mathrm{2}\right){y}=\mathrm{0} \\ $$ Answered by mindispower last updated on 16/Nov/21 $${x}\left({y}''+\mathrm{2}{y}'+{y}\right)+\left({y}'+{y}\right) \\ $$$$={x}\left(\left({y}'+{y}\right)'+\left({y}'+{y}\right)\right)+\left({y}'+{y}\right)=\mathrm{0} \\ $$$${z}={y}+{y}'…
Question Number 93786 by mr W last updated on 14/May/20 $${find}\:{f}\left({x}\right)\:{such}\:{that} \\ $$$${f}\:'\left({x}\right)={f}^{−\mathrm{1}} \left({x}\right) \\ $$ Answered by john santu last updated on 15/May/20 $$\mathrm{f}\left(\mathrm{x}\right)=\:\sqrt[{\varphi}]{\frac{\mathrm{1}}{\varphi}}\:\mathrm{x}^{\varphi}…
Question Number 159319 by nimnim last updated on 15/Nov/21 $$\:\:\:\:\:\:\:\frac{\mathrm{dy}}{\mathrm{dx}}+\frac{\mathrm{x}−\mathrm{y}−\mathrm{2}}{\mathrm{x}−\mathrm{2y}−\mathrm{3}}=\mathrm{0} \\ $$$$\mathrm{Pls}…\:\mathrm{solve}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation}. \\ $$ Answered by mr W last updated on 15/Nov/21 $${let} \\ $$$${x}={u}+{a}…
Question Number 93707 by i jagooll last updated on 14/May/20 $$\mathrm{y}\:\mathrm{y}''\:=\:\left(\mathrm{y}'\right)^{\mathrm{2}} \: \\ $$ Commented by i jagooll last updated on 14/May/20 cool man Commented by…
Question Number 93620 by i jagooll last updated on 14/May/20 $$\left(\mathrm{3x}+\mathrm{3y}−\mathrm{4}\right)\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{x}+\mathrm{y}\: \\ $$ Answered by john santu last updated on 14/May/20 $${r}\:=\:{x}+{y}\:\Rightarrow\:\frac{{dr}}{{dx}}\:=\:\mathrm{1}+\:\frac{{dy}}{{dx}} \\ $$$$\left(\mathrm{3}{r}−\mathrm{4}\right)\left(\frac{{dr}}{{dx}}−\mathrm{1}\right)\:=\:{r}\: \\…