Question Number 92702 by i jagooll last updated on 08/May/20 $${y}''+\mathrm{2}{y}'−\mathrm{3}{y}={e}^{{x}} +{e}^{\mathrm{2}{x}} \\ $$ Answered by niroj last updated on 08/May/20 $$\:\:\mathrm{y}^{''} +\mathrm{2y}^{'} −\mathrm{3y}=\:\mathrm{e}^{\mathrm{x}} +\:\mathrm{e}^{\mathrm{2x}}…
Question Number 27028 by sorour87 last updated on 01/Jan/18 $${y}^{\left(\mathrm{2}\right)} +\mathrm{4}{y}=\mathrm{sinh}\:{x}×\mathrm{sin}\:\mathrm{2}{x} \\ $$ Answered by prakash jain last updated on 02/Jan/18 $$\lambda^{\mathrm{2}} +\mathrm{4}=\mathrm{0} \\ $$$$\lambda=\pm\mathrm{2}{i}…
Question Number 158087 by cortano last updated on 31/Oct/21 $$\left({y}^{\mathrm{2}} +\mathrm{4}{y}+\mathrm{8}\right){dx}+\sqrt{\mathrm{2}{x}+\mathrm{5}}\:\left({y}+\mathrm{3}\right){dy}=\mathrm{0}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 26983 by chernoaguero@gmail.com last updated on 31/Dec/17 $$\mathrm{Find}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:\:\:\: \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{y}} =\mathrm{y}^{\mathrm{x}} \\ $$ Answered by mrW1 last updated on 31/Dec/17 $${y}\:\mathrm{ln}\:{x}={x}\:\mathrm{ln}\:{y} \\ $$$${y}'\:\mathrm{ln}\:{x}+\frac{{y}}{{x}}=\mathrm{ln}\:{y}+\frac{{x}}{{y}}\:{y}'…
Question Number 92468 by jagoll last updated on 07/May/20 $$\mathrm{y}\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}}−\mathrm{9y}\:=\:\mathrm{3} \\ $$ Answered by mr W last updated on 07/May/20 $${u}=\frac{{dy}}{{dx}} \\ $$$${yu}\frac{{du}}{{dy}}−\mathrm{9}{y}=\mathrm{3} \\…
Question Number 92464 by jagoll last updated on 07/May/20 $$\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{e}^{\mathrm{y}} }{\mathrm{x}^{\mathrm{2}} }\:−\:\frac{\mathrm{1}}{\mathrm{x}} \\ $$ Commented by mr W last updated on 07/May/20 $${how}\:{do}\:{you}\:{get} \\ $$$$\frac{{dy}}{{e}^{{y}}…
Question Number 92452 by jagoll last updated on 07/May/20 $$\left(\mathrm{2xy}^{\mathrm{2}} −\mathrm{y}\right)\mathrm{dx}\:=\:\left(\mathrm{2x}−\mathrm{x}^{\mathrm{2}} \mathrm{y}\right)\mathrm{dy}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 157982 by tounghoungko last updated on 30/Oct/21 $$\:\left(\mathrm{3}{x}^{\mathrm{2}} −\mathrm{4}{xy}+{y}^{\mathrm{2}} −\mathrm{3}{y}\right){dx}+\left(\mathrm{2}{xy}−\mathrm{2}{x}^{\mathrm{2}} +\mathrm{6}{y}^{\mathrm{2}} +\mathrm{3}{x}\right){dy}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 26904 by sorour87 last updated on 31/Dec/17 $${y}^{\left(\mathrm{2}\right)} +{y}=\mathrm{sec}\:^{\mathrm{3}} {x} \\ $$ Commented by prakash jain last updated on 31/Dec/17 $${g}\left({x}\right)=\mathrm{sec}^{\mathrm{3}} {x} \\…
Question Number 92398 by jagoll last updated on 06/May/20 $$\mathrm{x}^{\mathrm{3}} \:\left(\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\right)\:+\mathrm{x}^{\mathrm{2}} \left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{\mathrm{2}} \:=\:\mathrm{ln}\:\left(\mathrm{x}\right)\: \\ $$ Answered by Joel578 last updated on 06/May/20 Commented…