Question Number 92452 by jagoll last updated on 07/May/20 $$\left(\mathrm{2xy}^{\mathrm{2}} −\mathrm{y}\right)\mathrm{dx}\:=\:\left(\mathrm{2x}−\mathrm{x}^{\mathrm{2}} \mathrm{y}\right)\mathrm{dy}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 157982 by tounghoungko last updated on 30/Oct/21 $$\:\left(\mathrm{3}{x}^{\mathrm{2}} −\mathrm{4}{xy}+{y}^{\mathrm{2}} −\mathrm{3}{y}\right){dx}+\left(\mathrm{2}{xy}−\mathrm{2}{x}^{\mathrm{2}} +\mathrm{6}{y}^{\mathrm{2}} +\mathrm{3}{x}\right){dy}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 26904 by sorour87 last updated on 31/Dec/17 $${y}^{\left(\mathrm{2}\right)} +{y}=\mathrm{sec}\:^{\mathrm{3}} {x} \\ $$ Commented by prakash jain last updated on 31/Dec/17 $${g}\left({x}\right)=\mathrm{sec}^{\mathrm{3}} {x} \\…
Question Number 92398 by jagoll last updated on 06/May/20 $$\mathrm{x}^{\mathrm{3}} \:\left(\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\right)\:+\mathrm{x}^{\mathrm{2}} \left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{\mathrm{2}} \:=\:\mathrm{ln}\:\left(\mathrm{x}\right)\: \\ $$ Answered by Joel578 last updated on 06/May/20 Commented…
Question Number 26837 by sorour87 last updated on 30/Dec/17 $${xy}^{\left(\mathrm{2}\right)} ={y}^{\left(\mathrm{1}\right)} ×\mathrm{ln}\:\frac{{y}^{\left(\mathrm{1}\right)} }{{x}} \\ $$ Answered by prakash jain last updated on 30/Dec/17 $${y}'={u}\left({x}\right) \\…
Question Number 157784 by Dhetal last updated on 27/Oct/21 $${from}\:{the}\:{partical}\:{differential}\:{equation}\:{by}\:{eliminating}\:{constants}\:{indicated}\:{in}\:{brackets}\:{from}\:{the}\:{following}\:{equation}\:{z}=\left({x}+{a}\right)\:\left({y}+{b}\right);\left({a},{b}\right) \\ $$ Commented by Tawa11 last updated on 27/Oct/21 $$\mathrm{Great}\:\mathrm{sir} \\ $$ Commented by Ali_Adily…
Question Number 91911 by jagoll last updated on 03/May/20 $$\mathrm{y}''''+\mathrm{2y}''+\mathrm{y}=\mathrm{sin}\:\mathrm{x}\: \\ $$ Answered by niroj last updated on 03/May/20 $$\:\:\mathrm{y}^{''''} +\mathrm{2y}^{''} +\mathrm{y}=\:\mathrm{sin}\:\mathrm{x} \\ $$$$\:\:\:\frac{\mathrm{d}^{\mathrm{4}} \mathrm{y}}{\mathrm{dx}^{\mathrm{4}}…
Question Number 26368 by d.monhbayr@gmail.com last updated on 24/Dec/17 $${y}={a}^{\mathrm{arc}{tg}\sqrt{{x}}} \\ $$$${derivative}\:? \\ $$ Commented by kaivan.ahmadi last updated on 24/Dec/17 $$\mathrm{log}_{\mathrm{a}} \mathrm{y}=\mathrm{arctg}\sqrt{\mathrm{x}}\Rightarrow\frac{\mathrm{y}'}{\mathrm{y}}\mathrm{lna}=\frac{\left(\sqrt{\mathrm{x}}\right)^{'} }{\mathrm{1}+\left(\sqrt{\mathrm{x}}\right)^{\mathrm{2}} }=…
Question Number 26365 by d.monhbayr@gmail.com last updated on 24/Dec/17 $${y}=\mathrm{log}_{{a}} \left({x}^{\mathrm{2}} −\mathrm{16}\right) \\ $$ Commented by mrW1 last updated on 24/Dec/17 $${what}\:{is}\:{your}\:{question}? \\ $$ Terms…
Question Number 26364 by d.monhbayr@gmail.com last updated on 24/Dec/17 $${y}={x}^{\mathrm{2}} \left({x}−\mathrm{1}\right)^{\mathrm{2}} \\ $$$${min}=?\:\:\:{max}=? \\ $$$${help}\:{pls} \\ $$ Commented by mrW1 last updated on 24/Dec/17 $${there}\:{is}\:{no}\:{max},\:{since}\:{y}\rightarrow\infty\:{when}\:{x}\rightarrow\pm\infty.…