Category: Differential Equation

Question Number 91211 by john santu last updated on 28/Apr/20 $${x}\:{dy}\:+\mathrm{5}{y}\:{dx}\:=\:\mathrm{2}{y}^{\mathrm{4}} {x}\:{dx} \\ $$ Commented by john santu last updated on 29/Apr/20 Answered by MWSuSon…

Question Number 91139 by john santu last updated on 28/Apr/20 $$\frac{{dy}}{{dx}}\:=\:\frac{{y}−{x}+\mathrm{1}}{{y}−{x}+\mathrm{5}} \\ $$ Commented by john santu last updated on 28/Apr/20 $$\frac{{dy}}{{dx}}\:=\:\frac{{y}−{x}+\mathrm{5}−\mathrm{4}}{{y}−{x}+\mathrm{5}}\:=\:\mathrm{1}−\frac{\mathrm{4}}{{y}−{x}+\mathrm{5}} \\ $$$$\left[\:{let}\:{Q}={y}−{x}\:\right]\: \\…

Question Number 91012 by jagoll last updated on 27/Apr/20 $$\frac{{dy}}{{dx}}\:+\:\mathrm{2}{xy}\:=\:{xe}^{−{x}^{\mathrm{2}} } {y}^{\mathrm{3}} \\ $$ Answered by john santu last updated on 27/Apr/20 Terms of Service…

Question Number 90983 by jagoll last updated on 27/Apr/20 $${y}''−\mathrm{5}{y}'+\mathrm{6}{y}={x}^{\mathrm{2}} \\ $$ Commented by john santu last updated on 27/Apr/20 $$\mathrm{complementari}\:\mathrm{solution} \\ $$$$\mathrm{y}\:=\:\mathrm{Ae}^{\mathrm{q}_{\mathrm{1}} \mathrm{x}} \:+\:\mathrm{Be}^{\mathrm{q}_{\mathrm{2}}…

Question Number 90955 by jagoll last updated on 27/Apr/20 $${y}''−\mathrm{5}{y}'−\mathrm{24}{y}={e}^{\mathrm{3}{x}} \\ $$$$ \\ $$ Commented by jagoll last updated on 27/Apr/20 $${i}\:{got}\: \\ $$$${y}_{{h}} \:=\:{Ae}^{\mathrm{8}{x}}…