Question Number 91287 by jagoll last updated on 29/Apr/20 $${y}''+\mathrm{2}{y}'+\mathrm{5}{y}=\mathrm{3sin}\:\mathrm{4}{t} \\ $$ Answered by niroj last updated on 29/Apr/20 $$\:\:\:\mathrm{y}^{''} +\mathrm{2y}'+\mathrm{5y}=\:\mathrm{3sin}\:\mathrm{4t} \\ $$$$\:\:\left(\mathrm{D}^{\mathrm{2}} +\mathrm{2D}+\mathrm{5}\right)\mathrm{y}=\:\mathrm{3sin}\:\mathrm{4t}\:\: \\…
Question Number 91272 by jagoll last updated on 29/Apr/20 $$\left({D}^{\mathrm{2}} +\mathrm{4}\right){y}\:=\:\mathrm{sin}\:\mathrm{2}{x} \\ $$ Answered by niroj last updated on 29/Apr/20 $$\:\left(\mathrm{D}^{\mathrm{2}} +\mathrm{4}\right)\mathrm{y}=\:\mathrm{sin2x} \\ $$$$\:\mathrm{A}.\mathrm{E}.,\:\:\mathrm{m}^{\mathrm{2}} +\mathrm{4}=\mathrm{0}…
Question Number 91263 by jagoll last updated on 29/Apr/20 $${y}''''\:+\mathrm{2}{y}''+{y}\:=\:\mathrm{sin}\:{x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 91228 by ~blr237~ last updated on 28/Apr/20 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\:{lnx}\left(\int_{\mathrm{0}} ^{{x}} \:\frac{{dt}}{{lnt}}\:\right)\: \\ $$ Commented by abdomathmax last updated on 29/Apr/20 $$={lim}_{{x}\rightarrow\mathrm{1}} \:\left({x}−\mathrm{1}\right){lnx}\:×\frac{\int_{\mathrm{0}} ^{{x}}…
Question Number 91211 by john santu last updated on 28/Apr/20 $${x}\:{dy}\:+\mathrm{5}{y}\:{dx}\:=\:\mathrm{2}{y}^{\mathrm{4}} {x}\:{dx} \\ $$ Commented by john santu last updated on 29/Apr/20 Answered by MWSuSon…
Question Number 91147 by john santu last updated on 28/Apr/20 $$\left({D}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} {y}\:=\:{x}^{\mathrm{2}} \mathrm{cos}\:{x}\: \\ $$ Commented by MWSuSon last updated on 28/Apr/20 I've corrected the mistake. Answered…
Question Number 91139 by john santu last updated on 28/Apr/20 $$\frac{{dy}}{{dx}}\:=\:\frac{{y}−{x}+\mathrm{1}}{{y}−{x}+\mathrm{5}} \\ $$ Commented by john santu last updated on 28/Apr/20 $$\frac{{dy}}{{dx}}\:=\:\frac{{y}−{x}+\mathrm{5}−\mathrm{4}}{{y}−{x}+\mathrm{5}}\:=\:\mathrm{1}−\frac{\mathrm{4}}{{y}−{x}+\mathrm{5}} \\ $$$$\left[\:{let}\:{Q}={y}−{x}\:\right]\: \\…
Question Number 91024 by john santu last updated on 27/Apr/20 $${x}^{\mathrm{2}} {y}''+\mathrm{3}{xy}'\:+\mathrm{2}{y}\:=\:\mathrm{4}{x}^{\mathrm{2}} \\ $$ Commented by jagoll last updated on 27/Apr/20 $${i}\:{can}\:{try} \\ $$$${let}\:{x}\:=\:{e}^{{z}} \\…
Question Number 91012 by jagoll last updated on 27/Apr/20 $$\frac{{dy}}{{dx}}\:+\:\mathrm{2}{xy}\:=\:{xe}^{−{x}^{\mathrm{2}} } {y}^{\mathrm{3}} \\ $$ Answered by john santu last updated on 27/Apr/20 Terms of Service…
Question Number 91010 by jagoll last updated on 27/Apr/20 $${solve}\:{the}\:{diff}\:{eq}\: \\ $$$${y}'''−{y}''+\mathrm{4}{y}'−\mathrm{4}{y}=\:{e}^{{x}} \\ $$ Commented by john santu last updated on 27/Apr/20 $${the}\:{characteristic}\:{equation}\: \\ $$$${w}^{\mathrm{3}}…