Category: Differential Equation

Question Number 89632 by jagoll last updated on 18/Apr/20 $$\mathrm{y}\sqrt{{\mathrm{x}}^2-1}\mathrm{dx}+\mathrm{x}\sqrt{{\mathrm{y}}^2-1}\mathrm{dy}=0$$ Answered by john santu last updated on 18/Apr/20 Terms of Service…

Question Number 89600 by jagoll last updated on 18/Apr/20 $$\frac{\mathrm{dy}}{\mathrm{dx}}=\frac{\mathrm{y}+\sqrt{{\mathrm{x}}^2-{\mathrm{y}}^2}}{\mathrm{x}}$$ Commented by mr W last updated on 18/Apr/20 $$\frac{{dy}}{{dx}}=\frac{{y}}{{x}}+\sqrt{\mathrm{1}−\left(\frac{{y}}{{x}}\right)^{\mathrm{2}} } \…

Question Number 89205 by jagoll last updated on 16/Apr/20 $$2\frac{dy}{dx}=\frac{y}{x}+{\left(\frac{y}{x}\right)}^2$$ Commented by john santu last updated on 16/Apr/20 $$y=vx\Rightarrow \frac{dy}{dx}=v+x\frac{dv}{dx}$$$$2v+2x\frac{dv}{dx}=v+v^2$$$$\mathrm{2}{x}\:\frac{{dv}}{{dx}}\:=\:{v}^{\mathrm{2}}…

Question Number 23524 by tawa tawa last updated on 01/Nov/17 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 23445 by tawa tawa last updated on 30/Oct/17 $$\mathrm{Solve}\mathrm{the}\mathrm{equation}:\frac{{\partial }^2\mathrm{u}}{\partial \mathrm{x}\partial \mathrm{y}}=\sin \left(\mathrm{x}\right)\cos \left(\mathrm{y}\right),\mathrm{subjected}\mathrm{to}\mathrm{the}\mathrm{boundary}$$$$\mathrm{conditions}\mathrm{at}\mathrm{y}=\frac{\pi }{2},\frac{\partial \mathrm{u}}{\partial \mathrm{x}}=2\mathrm{x}\mathrm{and}\mathrm{x}=\pi ,\mathrm{u}=2\sin \left(\mathrm{y}\right)$$ Answered by mrW1 last updated on 31/Oct/17 $$\:\frac{\partial^{\mathrm{2}} \mathrm{u}}{\partial\mathrm{x}\partial\mathrm{y}}\:=\:\mathrm{sin}\left(\mathrm{x}\right)\mathrm{cos}\left(\mathrm{y}\right)…