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Category: Differential Equation

y-4y-5y-1-8cos-x-e-2x-

Question Number 88492 by jagoll last updated on 11/Apr/20 $$\mathrm{y}''\:−\mathrm{4y}'+\mathrm{5y}\:=\:\mathrm{1}+\mathrm{8cos}\:\mathrm{x}+\mathrm{e}^{\mathrm{2x}} \\ $$ Commented by niroj last updated on 11/Apr/20 $$\:\:\frac{\boldsymbol{\mathrm{d}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{dx}}^{\mathrm{2}} }−\mathrm{4}\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}+\mathrm{5}\boldsymbol{\mathrm{y}}=\:\mathrm{1}+\mathrm{8}\boldsymbol{\mathrm{cos}}\:\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{e}}^{\mathrm{2}\boldsymbol{\mathrm{x}}} \\ $$$$\:\:\left(\mathrm{D}^{\mathrm{2}} −\mathrm{4D}+\mathrm{5}\right)\mathrm{y}=\:\mathrm{1}+\mathrm{8cos}\:\mathrm{x}\:+\mathrm{e}^{\mathrm{2x}}…

How-to-solve-this-homogeneous-equation-Can-u-help-me-plz-Q-solve-x-sin-y-x-dy-y-sin-1-y-x-dx-0-

Question Number 22535 by Arjun Daniel last updated on 19/Oct/17 $$\mathrm{H}{ow}\:{to}\:{solve}\:{this}\:{homogeneous}\:{equation}.\:{Can}\:{u}\:{help}\:{me}\:{plz} \\ $$$${Q}.\:{solve}\:\left({x}\:{sin}\:\frac{{y}}{{x}}\right){dy}\:−\left({y}\:{sin}^{−\mathrm{1}} \:\frac{{y}}{{x}}\right){dx}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

y-y-sec-x-

Question Number 153542 by EDWIN88 last updated on 08/Sep/21 $$\:{y}'''+{y}'=\mathrm{sec}\:{x}\: \\ $$ Answered by puissant last updated on 08/Sep/21 $${y}'''+{y}'={secx} \\ $$$$\Rightarrow\:{y}''+{y}={ln}\left({tan}\left(\frac{{x}}{\mathrm{2}}+\frac{\pi}{\mathrm{2}}\right)\right)+{C}_{\mathrm{1}} \\ $$$$\Rightarrow\:\left({D}^{\mathrm{2}} +{D}\right){y}={ln}\left({tan}\left(\frac{{x}}{\mathrm{2}}+\frac{\pi}{\mathrm{2}}\right)\right)+{C}_{\mathrm{1}}…

y-3y-2y-10sin-x-2cos-2x-

Question Number 87904 by john santu last updated on 07/Apr/20 $$\mathrm{y}\:''\:−\mathrm{3y}'\:+\mathrm{2y}\:=\:\mathrm{10sin}\:\mathrm{x}\:+\:\mathrm{2cos}\:\mathrm{2x} \\ $$ Commented by niroj last updated on 07/Apr/20 $$\:\:\mathrm{y}^{''} −\mathrm{3y}^{'} +\mathrm{2y}=\mathrm{10sin}\:\mathrm{x}+\mathrm{2cos}\:\mathrm{2x} \\ $$$$\:\:\:\left(\mathrm{D}^{\mathrm{2}}…