Question Number 250 by 123456 last updated on 25/Jan/15 $$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }+\mathrm{2}{x}\left(\frac{{dy}}{{dx}}\right)^{\mathrm{2}} =\mathrm{0} \\ $$ Answered by prakash jain last updated on 17/Dec/14 $$\frac{{dy}}{{dx}}={u} \\…
Question Number 131315 by Engr_Jidda last updated on 03/Feb/21 $${Given}\:{that}\:{y}_{{n}} \left({t}\right)=\varrho^{{t}} {B}_{{n}} {sin}\frac{{n}\pi}{\mathrm{4}}{t} \\ $$$${Evaluate}\:\int_{\mathrm{0}} ^{\mathrm{4}} \left[{y}_{{n}} \left({t}\right)\right]^{\mathrm{2}} {dt} \\ $$ Answered by Ar Brandon…
Question Number 236 by 123456 last updated on 25/Jan/15 $$\mathrm{solve} \\ $$$${y}''−{y}'−{y}={e}^{{x}} +{e}^{\mathrm{2}{x}} \\ $$$$\begin{cases}{{y}\left(\mathrm{0}\right)+{y}'\left(\mathrm{0}\right)=\mathrm{1}}\\{{y}\left(\mathrm{0}\right)−{y}'\left(\mathrm{0}\right)=\mathrm{0}}\end{cases} \\ $$ Answered by prakash jain last updated on 17/Dec/14…
Question Number 224 by 123456 last updated on 25/Jan/15 $$\mathrm{solve} \\ $$$${x}\frac{{dy}}{{dx}}+{y}=\alpha{x}+\beta \\ $$ Answered by mreddy last updated on 16/Dec/14 $$\frac{{dy}}{{dx}}+\frac{{y}}{{x}}=\frac{\alpha{x}+\beta}{{x}} \\ $$$$\mathrm{Integrating}\:\mathrm{Factor}={e}^{\int\frac{\mathrm{1}}{{x}}{dx}} ={e}^{\mathrm{ln}\:{x}}…
Question Number 182 by sudhanshur last updated on 25/Jan/15 $$\mathrm{solve}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$\left({e}^{{y}} +\mathrm{1}\right)\mathrm{cos}\:{x}\:{dx}+{e}^{{y}} \mathrm{sin}\:{x}\:{dy}=\mathrm{0} \\ $$ Answered by 123456 last updated on 14/Dec/14 $$\mathrm{we}\:\mathrm{have}\:\left({e}^{{y}} +\mathrm{1}\right)\mathrm{cos}\:{x}\:{dx}+{e}^{{y}}…
Question Number 131253 by bramlexs22 last updated on 03/Feb/21 $${Solve}\:\left({D}^{\mathrm{2}} −\mathrm{3}{D}+\mathrm{2}\right){y}\:=\:\mathrm{2}{x}^{\mathrm{3}} \\ $$$${by}\:{operator}\:{D}\:{method}\: \\ $$ Answered by liberty last updated on 03/Feb/21 $$\mathrm{y}_{\mathrm{h}} \left(\mathrm{x}\right)=\:\mathrm{C}_{\mathrm{1}} \mathrm{e}^{\mathrm{x}}…
Question Number 131194 by john_santu last updated on 02/Feb/21 $$\:\mathrm{6}{y}^{\mathrm{3}} \:{dx}\:+\:\mathrm{2}{x}\:{dy}\:=\:\left({x}+\mathrm{1}\right)\:{dx}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 131086 by EDWIN88 last updated on 01/Feb/21 $$\:{y}''−{y}\:=\:{e}^{−\mathrm{2}{x}} \:\mathrm{sin}\:\left({e}^{−{x}} \right)\: \\ $$ Answered by liberty last updated on 01/Feb/21 $$\left[\:\mathrm{D}^{\mathrm{2}} −\mathrm{1}\:\right]\mathrm{y}\:=\:\mathrm{e}^{−\mathrm{2x}} \mathrm{sin}\:\left(\mathrm{e}^{−\mathrm{x}} \right)…
Question Number 143878 by akmalovna05 last updated on 19/Jun/21 $$\mathrm{y}'''=\mathrm{2xy}'' \\ $$ Answered by Ar Brandon last updated on 19/Jun/21 $$\mathrm{y}'''=\mathrm{2xy}''\Rightarrow\frac{\mathrm{y}'''}{\mathrm{y}''}=\mathrm{2x}\Rightarrow\mathrm{ln}\left(\mathrm{y}''\right)=\mathrm{x}^{\mathrm{2}} \Rightarrow\mathrm{y}''=\mathrm{e}^{\mathrm{x}^{\mathrm{2}} } \\ $$…
Question Number 143874 by akmalovna05 last updated on 19/Jun/21 $$\mathrm{y}''−\mathrm{x}×\mathrm{y}'''+\mathrm{y}'''^{\mathrm{3}} =\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com