Question Number 129110 by math178 last updated on 12/Jan/21 Commented by math178 last updated on 12/Jan/21 $${differential}\:{equation}\:{general}\:{solver}\:?\:{thank}\:{you} \\ $$ Answered by mr W last updated…
Question Number 128971 by Ahmed1hamouda last updated on 11/Jan/21 $${solve}\:{the}\:{following}\:{equation} \\ $$$$\left({x}\mathrm{tan}\left(\frac{{y}}{{x}}\right)−{y}\mathrm{sec}^{\mathrm{2}} \left(\frac{{y}}{{x}}\right)\right){dx}−{x}\mathrm{sec}^{\mathrm{2}} \left(\frac{{y}}{{x}}\right){dy}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 63407 by ugwu Kingsley last updated on 03/Jul/19 $${find}\:{a}\:{basics}\:{of}\:{solution}\:{of}\:{the}\:{ode} \\ $$$$ \\ $$$$\left({x}^{\mathrm{2}} −{x}\right){y}''\:−{xy}'+{y}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 128689 by bemath last updated on 09/Jan/21 $$\:\left(\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} \right)\:\mathrm{dx}\:=\:\mathrm{3xy}^{\mathrm{2}} \:\mathrm{dy}\: \\ $$ Answered by liberty last updated on 09/Jan/21 $$\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} }{\mathrm{3xy}^{\mathrm{2}}…
Question Number 128667 by sarahvalencia last updated on 09/Jan/21 Commented by liberty last updated on 09/Jan/21 $$\:\left(\mathrm{1}\right)\:\mathrm{a}^{\mathrm{2}} \mathrm{da}\:+\:\mathrm{2ab}\:\mathrm{db}\:+\:\mathrm{b}^{\mathrm{2}} \:\mathrm{da}\:=\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\mathrm{d}\left(\mathrm{ab}^{\mathrm{2}} \right)\:+\:\mathrm{a}^{\mathrm{2}} \:\mathrm{da}\:=\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\int\:\mathrm{d}\left(\mathrm{ab}^{\mathrm{2}}…
Question Number 128646 by Algoritm last updated on 09/Jan/21 Answered by Olaf last updated on 09/Jan/21 $${y}''−\frac{\mathrm{1}+{x}}{{x}}{y}'+\frac{{y}}{{x}}\:=\:\mathrm{0}\:\left(\mathrm{1}\right) \\ $$$${y}''−{y}'−\frac{{y}'−{y}}{{x}}\:=\:\mathrm{0}\:\left(\mathrm{2}\right) \\ $$$$\mathrm{Let}\:{u}\:=\:{y}'−{y}\:\left(\mathrm{3}\right) \\ $$$$\left(\mathrm{2}\right)\::\:{u}'−\frac{{u}}{{x}}\:=\:\mathrm{0} \\ $$$$\frac{{u}'}{{u}}\:=\:\frac{\mathrm{1}}{{x}}…
Question Number 128579 by john_santu last updated on 08/Jan/21 $$\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{x}}{\mathrm{xy}^{\mathrm{2}} +\mathrm{y}}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 128536 by liberty last updated on 08/Jan/21 $$\mathrm{Solution}\:\mathrm{of}\:\mathrm{differential}\:\mathrm{eq}\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{y}\left(\mathrm{x}−\mathrm{y}\:\mathrm{ln}\:\mathrm{y}\right)}{\mathrm{x}\left(\mathrm{x}\:\mathrm{ln}\:\mathrm{x}−\mathrm{y}\right)}\:. \\ $$$$\mathrm{is}\:\_ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 128432 by bemath last updated on 07/Jan/21 $$\left(\mathrm{3x}^{\mathrm{2}} +\mathrm{1}\right)\mathrm{yy}'\:+\mathrm{3xy}^{\mathrm{2}} =\mathrm{cos}\:\mathrm{x}.\mathrm{e}^{\mathrm{sin}\:\mathrm{x}} \: \\ $$ Answered by liberty last updated on 07/Jan/21 $$\mathrm{let}\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{v}\left(\mathrm{x}\right)\Rightarrow\mathrm{2yy}'=\frac{\mathrm{dv}}{\mathrm{dx}} \\…
Question Number 128420 by bramlexs22 last updated on 07/Jan/21 $$\:\mathrm{y}'=\mathrm{2y}\:\mathrm{sin}\:\mathrm{x}\:−\mathrm{2y}^{\mathrm{3}/\mathrm{2}} \:\mathrm{sin}\:\mathrm{x}\: \\ $$ Answered by liberty last updated on 07/Jan/21 $$\mathrm{y}'=\mathrm{2sin}\:\mathrm{x}\left(\mathrm{y}−\mathrm{y}^{\mathrm{3}/\mathrm{2}} \right) \\ $$$$\frac{\mathrm{dy}}{\mathrm{y}−\mathrm{y}^{\mathrm{3}/\mathrm{2}} }\:=\:\mathrm{2sin}\:\mathrm{x}\:\mathrm{dx}\:…