Question Number 71516 by oyemi kemewari last updated on 16/Oct/19 $$\mathrm{5y}''=\left(\mathrm{1}+\mathrm{y}'^{\mathrm{2}} \right)^{\frac{\mathrm{3}}{\mathrm{2}}} \\ $$$$\mathrm{please}\:\mathrm{solve}\:\mathrm{the}\:\mathrm{differtial}\:\mathrm{equation} \\ $$ Answered by mind is power last updated on 17/Oct/19…
Question Number 137027 by liberty last updated on 29/Mar/21 $$\mathrm{2x}\:\mathrm{dx}\:+\:\mathrm{x}^{−\mathrm{2}} \left(\mathrm{x}\:\mathrm{dy}−\mathrm{y}\:\mathrm{dx}\right)\:=\:\mathrm{0} \\ $$ Answered by bobhans last updated on 29/Mar/21 Terms of Service Privacy Policy…
Question Number 5908 by sanusihammed last updated on 04/Jun/16 $${Solve}\:\: \\ $$$$\frac{{dy}}{{dx}}\:\:−\:{y}\:{tan}\:{x}\:\:=\:{y}^{\mathrm{2}} \:{tan}^{\mathrm{2}} \:{x} \\ $$$$ \\ $$$${please}\:{help}. \\ $$ Commented by 123456 last updated…
Question Number 136815 by rs4089 last updated on 26/Mar/21 Answered by Dwaipayan Shikari last updated on 26/Mar/21 $${y}={e}^{\lambda{x}} \\ $$$${x}^{\mathrm{2}} \lambda^{\mathrm{2}} +{x}\lambda+\left({x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{4}}\right)=\mathrm{0} \\ $$$$\Rightarrow\lambda=\frac{−{x}\pm\sqrt{{x}^{\mathrm{2}}…
Question Number 5587 by sanusihammed last updated on 21/May/16 $${Please}\:{i}\:{need}\:{your}\:{help}. \\ $$$$ \\ $$$${if}\:\:\:{y}\:\:=\:\:\left[{tanx}\right]^{\left[{tanx}\right]^{\left[{tanx}\right]} } \:\:\:.\:\:\:{find}\:\:{dy}/{dx}\:\:{at}\:\:\Pi/\mathrm{4} \\ $$ Commented by prakash jain last updated on…
Question Number 5208 by sanusihammed last updated on 30/Apr/16 $${If}\:{y}\:=\:{x}!\: \\ $$$$ \\ $$$${Find}\:\frac{{dy}}{{dx}} \\ $$ Commented by FilupSmith last updated on 30/Apr/16 $${x}!=\Gamma\left({x}+\mathrm{1}\right) \\…
Question Number 70720 by oyemi kemewari last updated on 07/Oct/19 $$\mathrm{y}''+\frac{\mathrm{y}'}{\mathrm{x}}+\frac{\mathrm{4y}}{\mathrm{x}^{\mathrm{2}} }=\mathrm{1}+\mathrm{x}^{\mathrm{2}} \\ $$ Commented by Rasheed.Sindhi last updated on 07/Oct/19 $$\mathcal{T}{hank}\:{you}! \\ $$ Commented…
Question Number 70694 by oyemi kemewari last updated on 07/Oct/19 Answered by mind is power last updated on 07/Oct/19 $${let}\:\frac{{y}'}{{x}}={u} \\ $$$$\Rightarrow{y}'={xu}\Rightarrow{y}''={u}+{xu}' \\ $$$${xy}''={xu}+{x}^{\mathrm{2}} {u}'…
Question Number 4915 by Yozzii last updated on 21/Mar/16 $${ln}\left(\frac{{d}\left\{{y}\left({x}\right)\right\}}{{dx}}\right)=\frac{{d}}{{dx}}\left({ln}\left\{{y}\left({x}\right)\right\}\right) \\ $$$${y}\left({x}\right)=? \\ $$ Commented by Yozzii last updated on 21/Mar/16 $${y}^{'} =\frac{{d}\left\{{y}\left({x}\right)\right\}}{{dx}} \\ $$$$\Rightarrow{lny}^{'}…
Question Number 70232 by Joel122 last updated on 02/Oct/19 $$\mathrm{Solve} \\ $$$${xy}'\:−\:{y}\:\mathrm{sin}\:{x}\:+\:{y}^{\mathrm{5}} \:=\:\mathrm{0} \\ $$ Commented by Joel122 last updated on 02/Oct/19 $$\mathrm{I}\:\mathrm{think}\:\mathrm{it}\:\mathrm{is}\:\mathrm{a}\:\mathrm{Bernoulli}'\mathrm{s}\:\mathrm{equation} \\ $$$${y}'\:−\:\left(\frac{\mathrm{sin}\:{x}}{{x}}\right){y}\:=\:−\frac{{y}^{\mathrm{5}}…