Question Number 2051 by Yozzi last updated on 01/Nov/15 $${Solve}\:{the}\:{d}.{e}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} \frac{{dy}}{{dx}}+{xy}+{x}^{\mathrm{2}} {y}^{\mathrm{2}} =\mathrm{1} \\ $$$${by}\:{letting}\:{y}=\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{v}}\:{where} \\ $$$${v}\:{is}\:{a}\:{function}\:{of}\:{x}.\: \\ $$ Answered by 123456 last…
Question Number 2050 by Yozzi last updated on 01/Nov/15 $${Solve}\:{the}\:{d}.{e} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{dy}}{{dx}}−{y}−\mathrm{3}{y}^{\mathrm{2}} =−\mathrm{2}\: \\ $$$${by}\:{letting}\:{y}=\frac{−\mathrm{1}}{\mathrm{3}{u}}\left(\frac{{du}}{{dx}}\right). \\ $$ Answered by 123456 last updated on 01/Nov/15 $${y}'=\frac{{dy}}{{dx}}…
Question Number 1898 by 123456 last updated on 22/Oct/15 $$\frac{{df}}{{dt}}=\alpha{f}+\beta{t}+\gamma \\ $$$${f}\left({t}\right)=?? \\ $$ Answered by Yozzy last updated on 22/Oct/15 $$\frac{{df}}{{dt}}=\alpha{f}+\beta{t}+\gamma\:\:\:{where}\:{I}\:{assume}\:{that}\:\alpha,\beta,\gamma\:{are}\:{constants}.\:{This}\:{equation}\:{may}\:{be} \\ $$$${rewritten}\:{as}\:\:\:\:\:\frac{{df}}{{dt}}−\alpha{f}=\beta{t}+\gamma\:\:\left(\ast\right).\:{The}\:{equation}\:{is}\:{a}\:{first}\:{order}\:{linear}\:{non}−{homogeneous} \\…
Question Number 67349 by Joel122 last updated on 26/Aug/19 $$\mathrm{Solve}\:\mathrm{for}\:{y}\left({x}\right) \\ $$$${xy}'\:=\:{y}\:+\:\mathrm{2}{x}^{\mathrm{3}} \mathrm{sin}^{\mathrm{2}} \left(\frac{{y}}{{x}}\right) \\ $$ Answered by mind is power last updated on 26/Aug/19…
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Question Number 132881 by Engr_Jidda last updated on 17/Feb/21 $${find}\:{the}\:{series}\:{solution}\:{of} \\ $$$${the}\:{ordinary}\:{differential}\:{equation} \\ $$$${y}^{\mathrm{2}} +\mathrm{2}{xy}^{\mathrm{1}} −\mathrm{3}{y}={x}^{\mathrm{2}} −\mathrm{1} \\ $$$${y}\left(\mathrm{0}\right)=\mathrm{1}\:{and}\:{y}^{\mathrm{1}} \left(\mathrm{0}\right)=\mathrm{2} \\ $$ Terms of Service…
Question Number 67336 by TawaTawa last updated on 25/Aug/19 $$\mathrm{If}\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{e}^{−\mathrm{t}} \:\:\frac{\mathrm{dy}}{\mathrm{dt}}\:\:,\:\:\:\:\:\:\mathrm{find}\:\:\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} } \\ $$ Commented by mr W last updated on 26/Aug/19 $${where}\:{did}\:{you}\:{get}\:{this}\:{question}? \\…
Question Number 1743 by 123456 last updated on 12/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}=? \\ $$ Commented by Rasheed Ahmad last updated on 13/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}'{v}+{uv}'−{u}'{v}'=\mathrm{0}…
Question Number 1603 by 123456 last updated on 25/Aug/15 $$\frac{{f}\left({x}\right)}{{f}'\left({x}\right)}=\frac{{f}'\left({x}\right)}{{f}\left({x}\right)} \\ $$$${f}\left({x}\right)= \\ $$ Answered by Rasheed Soomro last updated on 28/Aug/15 $$\left[\:{f}\:'\left({x}\right)\:\right]^{\mathrm{2}} =\left[\:{f}\left({x}\right)\:\right]^{\mathrm{2}} \\…
Question Number 1597 by Rasheed Ahmad last updated on 25/Aug/15 $$\int\frac{{f}\left({x}\right)}{{f}\:'\left({x}\right)}{dx}={ln}\:{sec}\:{x}+{c} \\ $$$${f}\left({x}\right)=? \\ $$ Answered by 123456 last updated on 25/Aug/15 $$\int\frac{{y}}{{dy}/{dx}}{dx}=\mathrm{ln}\:\mathrm{sec}\:{x}+{c} \\ $$$$\frac{{d}}{{dx}}\left[\int\frac{{y}}{{dy}/{dx}}{dx}\right]=\frac{{d}}{{dx}}\left[\mathrm{ln}\:\mathrm{sec}\:{x}+{c}\right]…
Question Number 1579 by 123456 last updated on 21/Aug/15 $$\left(\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\right)^{\mathrm{2}} +\frac{{dy}}{{dx}}+{y}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com