Question Number 129222 by bramlexs22 last updated on 14/Jan/21 $$\:\mathrm{y}−\mathrm{x}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{a}\left(\mathrm{y}^{\mathrm{2}} +\frac{\mathrm{dx}}{\mathrm{dy}}\:\right) \\ $$ Answered by bobhans last updated on 14/Jan/21 $$\:{y}−{xy}'\:=\:{ay}^{\mathrm{2}} +\frac{{a}}{{y}'} \\ $$$$\:{yy}'−{x}\left({y}'\right)^{\mathrm{2}} ={ay}^{\mathrm{2}}…
Question Number 129187 by math178 last updated on 13/Jan/21 Commented by math178 last updated on 13/Jan/21 $${differantial} \\ $$$${what}\:{is}\:{the}\:{special}\:{solution}? \\ $$$${thank}\:{you}\:<\mathrm{3} \\ $$ Answered by…
Question Number 129178 by Ahmed1hamouda last updated on 13/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129169 by math178 last updated on 13/Jan/21 Commented by math178 last updated on 13/Jan/21 $${differential}\:{equation}\:{special}\:{solution}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 129126 by benjo_mathlover last updated on 13/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{dy}}{\mathrm{dx}}−\mathrm{y}\:=\:\mathrm{xy}^{\mathrm{5}} \: \\ $$ Answered by liberty last updated on 13/Jan/21 $$\:\mathrm{let}\:\mathrm{v}\:=\:\mathrm{y}^{−\mathrm{4}} \:;\:\frac{\mathrm{dv}}{\mathrm{dx}}\:=−\mathrm{4y}^{−\mathrm{5}\:} \frac{\mathrm{dy}}{\mathrm{dx}} \\ $$$$\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:−\frac{\mathrm{1}}{\mathrm{4}}\mathrm{y}^{\mathrm{5}}…
Question Number 129110 by math178 last updated on 12/Jan/21 Commented by math178 last updated on 12/Jan/21 $${differential}\:{equation}\:{general}\:{solver}\:?\:{thank}\:{you} \\ $$ Answered by mr W last updated…
Question Number 128971 by Ahmed1hamouda last updated on 11/Jan/21 $${solve}\:{the}\:{following}\:{equation} \\ $$$$\left({x}\mathrm{tan}\left(\frac{{y}}{{x}}\right)−{y}\mathrm{sec}^{\mathrm{2}} \left(\frac{{y}}{{x}}\right)\right){dx}−{x}\mathrm{sec}^{\mathrm{2}} \left(\frac{{y}}{{x}}\right){dy}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 63407 by ugwu Kingsley last updated on 03/Jul/19 $${find}\:{a}\:{basics}\:{of}\:{solution}\:{of}\:{the}\:{ode} \\ $$$$ \\ $$$$\left({x}^{\mathrm{2}} −{x}\right){y}''\:−{xy}'+{y}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 128689 by bemath last updated on 09/Jan/21 $$\:\left(\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} \right)\:\mathrm{dx}\:=\:\mathrm{3xy}^{\mathrm{2}} \:\mathrm{dy}\: \\ $$ Answered by liberty last updated on 09/Jan/21 $$\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} }{\mathrm{3xy}^{\mathrm{2}}…
Question Number 128667 by sarahvalencia last updated on 09/Jan/21 Commented by liberty last updated on 09/Jan/21 $$\:\left(\mathrm{1}\right)\:\mathrm{a}^{\mathrm{2}} \mathrm{da}\:+\:\mathrm{2ab}\:\mathrm{db}\:+\:\mathrm{b}^{\mathrm{2}} \:\mathrm{da}\:=\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\mathrm{d}\left(\mathrm{ab}^{\mathrm{2}} \right)\:+\:\mathrm{a}^{\mathrm{2}} \:\mathrm{da}\:=\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\int\:\mathrm{d}\left(\mathrm{ab}^{\mathrm{2}}…