Question Number 1743 by 123456 last updated on 12/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}=? \\ $$ Commented by Rasheed Ahmad last updated on 13/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}'{v}+{uv}'−{u}'{v}'=\mathrm{0}…
Question Number 1603 by 123456 last updated on 25/Aug/15 $$\frac{{f}\left({x}\right)}{{f}'\left({x}\right)}=\frac{{f}'\left({x}\right)}{{f}\left({x}\right)} \\ $$$${f}\left({x}\right)= \\ $$ Answered by Rasheed Soomro last updated on 28/Aug/15 $$\left[\:{f}\:'\left({x}\right)\:\right]^{\mathrm{2}} =\left[\:{f}\left({x}\right)\:\right]^{\mathrm{2}} \\…
Question Number 1597 by Rasheed Ahmad last updated on 25/Aug/15 $$\int\frac{{f}\left({x}\right)}{{f}\:'\left({x}\right)}{dx}={ln}\:{sec}\:{x}+{c} \\ $$$${f}\left({x}\right)=? \\ $$ Answered by 123456 last updated on 25/Aug/15 $$\int\frac{{y}}{{dy}/{dx}}{dx}=\mathrm{ln}\:\mathrm{sec}\:{x}+{c} \\ $$$$\frac{{d}}{{dx}}\left[\int\frac{{y}}{{dy}/{dx}}{dx}\right]=\frac{{d}}{{dx}}\left[\mathrm{ln}\:\mathrm{sec}\:{x}+{c}\right]…
Question Number 1579 by 123456 last updated on 21/Aug/15 $$\left(\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\right)^{\mathrm{2}} +\frac{{dy}}{{dx}}+{y}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 1575 by 112358 last updated on 21/Aug/15 $${Solve}\:{the}\:{following}\:{D}.{E}. \\ $$$$\:\:\:\:\:\:\:\:\:\:\left(\frac{{dy}}{{dx}}\right)^{\mathrm{2}} +\mathrm{2}{y}+\mathrm{2}=\mathrm{0}\: \\ $$$${Does}\:\:\left(\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\right)^{\mathrm{2}} +\mathrm{2}{y}+\mathrm{2}=\mathrm{0}\:{have} \\ $$$${any}\:{solutions}\:{other}\:{than} \\ $$$${y}=−\mathrm{1}\:? \\ $$ Commented…
Question Number 132639 by Ahmed1hamouda last updated on 15/Feb/21 Commented by Ahmed1hamouda last updated on 15/Feb/21 $$\mathrm{solve}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation} \\ $$ Answered by mathmax by abdo last…
Question Number 132432 by Chhing last updated on 14/Feb/21 $$ \\ $$$$\:\:\mathrm{Solve}\:\:\mathrm{differential}\:\:\mathrm{equations} \\ $$$$\:\:\:\:\mathrm{1}/\:\left(\mathrm{x}^{\mathrm{3}} −\mathrm{1}\right)\mathrm{y}'+\mathrm{xy}=\mathrm{x} \\ $$$$\:\:\:\:\mathrm{2}/\:\left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)\mathrm{y}'−\mathrm{xy}+\frac{\mathrm{2x}}{\:\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }}=\mathrm{0} \\ $$$$\:\:\:\:\mathrm{3}/\:\mathrm{x}^{\mathrm{2}} \left(\mathrm{lnx}\right)\mathrm{y}''+\mathrm{y}=\mathrm{0}\:,\:\mathrm{know}\:\mathrm{that}\:\mathrm{y}=\mathrm{lnx}\:\mathrm{is}\:\mathrm{the}\:\mathrm{answer} \\ $$$$ \\…
Question Number 1352 by 112358 last updated on 24/Jul/15 $${Solve}\:{the}\:{following}\:{DE}\:: \\ $$$${y}\frac{{dy}}{{dx}}+\mathrm{6}{x}+\mathrm{5}{y}=\mathrm{0}\:\:\:\:\:\left({x}\neq\mathrm{0},{y}\neq\mathrm{0}\right) \\ $$ Answered by imhunter last updated on 27/Jul/15 $${q}.{no}.\mathrm{1352}\:\:\:\:\:\:\:\:\:\:\:{y}\:{dy}/{dx}=−\mathrm{6}{x}−\mathrm{5}{y} \\ $$$$ \\…
Question Number 1347 by prakash jain last updated on 24/Jul/15 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{following}\:\mathrm{DE} \\ $$$$\frac{{dy}}{{dx}}+\frac{{c}_{\mathrm{1}} }{{yx}^{\mathrm{2}} }={c}_{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 132398 by bramlexs22 last updated on 14/Feb/21 $$\mathrm{find}\:\mathrm{general}\:\mathrm{solution}\:\:\mathrm{y}'\:=\:\left(\mathrm{64x}+\mathrm{y}\right)^{\mathrm{2}} \: \\ $$ Answered by EDWIN88 last updated on 14/Feb/21 $$\mathrm{let}\:\mathrm{v}\:=\:\mathrm{64x}+\mathrm{y}\:\Leftrightarrow\frac{\mathrm{dv}}{\mathrm{dx}}\:=\:\mathrm{64}+\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$$$\mathrm{or}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{dv}}{\mathrm{dx}}−\mathrm{64}\: \\ $$$$\:\Leftrightarrow\:\frac{\mathrm{dv}}{\mathrm{dx}}\:\:−\:\mathrm{64}\:=\:\mathrm{v}^{\mathrm{2}}…