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Category: Differentiation

Question-26447

Question Number 26447 by yesaditya22@gmail.com last updated on 25/Dec/17 Commented by kaivan.ahmadi last updated on 25/Dec/17 $$\mathrm{y}=\mathrm{x}^{\mathrm{x}^{\mathrm{x}} } \Rightarrow\mathrm{lny}=\mathrm{x}^{\mathrm{x}} \mathrm{lnx}\Rightarrow\frac{\mathrm{y}^{'} }{\mathrm{y}}=\left(\mathrm{x}^{\mathrm{x}} \right)^{'} \mathrm{lnx}+\frac{\mathrm{x}^{\mathrm{x}} }{\mathrm{x}}\Rightarrow \