Question Number 152122 by peter frank last updated on 26/Aug/21 $$\sqrt{\mathrm{3}+\sqrt{\mathrm{6}+\sqrt{\mathrm{9}+…+\sqrt{\mathrm{96}+\sqrt{\mathrm{99}}}}}}\:=\:? \\ $$$$ \\ $$ Answered by peter frank last updated on 26/Aug/21 $$\mathrm{y}=\sqrt{\mathrm{3}+\mathrm{y}}\: \\…
Question Number 86537 by zainal tanjung last updated on 29/Mar/20 $$\mathrm{help}\: \\ $$$$\mathrm{given}\:\mathrm{total}\:\mathrm{cost}=\mathrm{4x}+\mathrm{y} \\ $$$$\mathrm{p}_{\mathrm{1}} =\mathrm{25}−\mathrm{3x}−\mathrm{2y} \\ $$$$\mathrm{p}_{\mathrm{2}} =\mathrm{12}−\mathrm{x}−\mathrm{y} \\ $$$$\mathrm{total}\:\mathrm{revenue}=\mathrm{p}_{\mathrm{1}} \mathrm{x}+\mathrm{p}_{\mathrm{2}} \mathrm{y} \\ $$$$\mathrm{calculate}:…
Question Number 20991 by Nafisat last updated on 09/Sep/17 $${x}^{\mathrm{3}} −\mathrm{12}{x} \\ $$ Commented by $@ty@m last updated on 10/Sep/17 $${what}\:{to}\:{do}? \\ $$ Terms of…
Question Number 20903 by ANTARES_VY last updated on 07/Sep/17 Answered by Joel577 last updated on 07/Sep/17 $$\mathrm{Using}\:\mathrm{polynomial}\:\mathrm{division},\mathrm{we}\:\mathrm{got} \\ $$$${I}\:=\:\int\:{x}^{\mathrm{3}} \:−\:{x}^{\mathrm{2}} \:+\:\mathrm{4}{x}\:−\:\mathrm{4}\:+\:\frac{\mathrm{4}{x}\:+\:\mathrm{1}}{{x}^{\mathrm{2}} \:+\:{x}}\:{dx} \\ $$$$\:\:\:=\:\int\:{x}^{\mathrm{3}} \:−\:{x}^{\mathrm{2}}…
Question Number 151965 by mnjuly1970 last updated on 24/Aug/21 $$ \\ $$$$\:\:\:{x}\:,\:{y}\:\in\:\mathbb{R}\: \\ $$$$\:\:\:\:\:\:\&\:{sin}\left({x}\:\right)+\:{cos}\:\left({y}\:\right)\:=\mathrm{1} \\ $$$${then}\:\:{max}\:\left(\:{sin}\left({y}\right)\:+\:{cos}\:\left({x}\right)\:\right)\:=? \\ $$$$\:\:…. \\ $$ Answered by mr W last…
Question Number 151954 by mnjuly1970 last updated on 24/Aug/21 $$ \\ $$$$\:\:\:\:{nice}…{calculus} \\ $$$$\: \\ $$$$\:\:\:\:\:\boldsymbol{\phi}\::=\:\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} {x}^{\:\mathrm{3}} .\:{cot}\:\left({x}\:\right){dx}\:=\frac{{a}}{\mathrm{16}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{a}\::=? \\ $$$${m}.{n}… \\ $$…
Question Number 20872 by j.masanja06@gmail.com last updated on 05/Sep/17 $${if}\:\:{y}=\left[{xtan}^{−\mathrm{1}} {x}\right]−\left[\frac{\mathrm{1}}{\mathrm{2}}{ln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\right] \\ $$$${show}\:{that}\:\left(\mathrm{1}+{x}^{\mathrm{2}} \right){y}^{''} =\mathrm{1} \\ $$ Answered by sma3l2996 last updated on 05/Sep/17…
Question Number 151940 by alcohol last updated on 24/Aug/21 Answered by qaz last updated on 24/Aug/21 $$\mathrm{4}\centerdot\mathrm{8}=\mathrm{32}……..\mathrm{32}\boldsymbol{\div}\mathrm{16}=\mathrm{2} \\ $$$$\mathrm{8}\centerdot\mathrm{9}=\mathrm{72}……..\mathrm{72}\boldsymbol{\div}\mathrm{24}=\mathrm{3} \\ $$$$\mathrm{9}\centerdot\mathrm{12}=\mathrm{108}…..\mathrm{108}\boldsymbol{\div}?=\mathrm{4} \\ $$$$\Rightarrow?=\mathrm{27} \\ $$…
Question Number 20871 by j.masanja06@gmail.com last updated on 05/Sep/17 Answered by sma3l2996 last updated on 05/Sep/17 $$\frac{{dy}}{{dx}}=\mathrm{2}\frac{{tan}^{−\mathrm{1}} {x}}{\mathrm{1}+{x}^{\mathrm{2}} }\Leftrightarrow\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\frac{{dy}}{{dx}}=\mathrm{2}{tan}^{−\mathrm{1}} {x} \\ $$$$\frac{{d}}{{dx}}\left(\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\frac{{dy}}{{dx}}\right)=\mathrm{2}\frac{{d}\left({tan}^{−\mathrm{1}} {x}\right)}{{dx}}=\frac{\mathrm{2}}{\mathrm{1}+{x}^{\mathrm{2}}…
Question Number 20870 by j.masanja06@gmail.com last updated on 05/Sep/17 Terms of Service Privacy Policy Contact: info@tinkutara.com