Question Number 84178 by www.abhisheksoni39@gmail.com last updated on 10/Mar/20 $$\mathrm{Find}\:\frac{{dy}}{{dx}}\:\mathrm{given}\:\mathrm{that}\:{y}\:=\:\left({sin}^{{n}} \:{x}\:{cosnx}\right) \\ $$ Answered by john santu last updated on 10/Mar/20 $$\mathrm{using}\:\mathrm{product}\:\mathrm{rule} \\ $$$$\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{nsin}^{\mathrm{n}−\mathrm{1}} \left(\mathrm{x}\right)\:\mathrm{cos}\:\left(\mathrm{x}\right)\mathrm{cos}\:\left(\mathrm{nx}\right)+…
Question Number 149667 by mnjuly1970 last updated on 06/Aug/21 $$\: \\ $$$${f}\:\left({x}\:\right)=\:\frac{\mathrm{1}}{\:\sqrt{\:\mathrm{1}\:+\:{sin}\:\left({x}\:\right)}\:+\sqrt{\:\mathrm{1}\:+\:{cos}\:\left({x}\right)}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{find}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{Min}\left(\:{f}\:\left({x}\right)\right)\:=? \\ $$$$ \\ $$ Answered by iloveisrael last updated…
Question Number 84067 by niroj last updated on 09/Mar/20 $$\:\mathrm{If}\:\boldsymbol{{lx}}+\boldsymbol{{my}}=\mathrm{1}\:\mathrm{touches}\:\mathrm{the}\:\mathrm{curve}\:\left(\boldsymbol{\mathrm{ax}}\right)^{\boldsymbol{\mathrm{n}}} +\left(\boldsymbol{\mathrm{by}}\right)^{\boldsymbol{\mathrm{n}}} =\mathrm{1},\:\mathrm{show}\:\mathrm{that} \\ $$$$\:\left(\frac{\boldsymbol{{l}}}{\boldsymbol{{a}}}\right)^{\frac{\boldsymbol{{n}}}{\boldsymbol{{n}}−\mathrm{1}}} +\left(\frac{\boldsymbol{{m}}}{\boldsymbol{{b}}}\right)^{\frac{\boldsymbol{{n}}}{\boldsymbol{{n}}−\mathrm{1}}} =\mathrm{1}. \\ $$ Answered by mind is power last updated…
Question Number 84065 by niroj last updated on 09/Mar/20 $$ \\ $$$$\: \\ $$$$\:\boldsymbol{\mathrm{Determine}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{b}}\:\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{order}}\:\boldsymbol{\mathrm{that}} \\ $$$$\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{0}} {\overset{\boldsymbol{\mathrm{lim}}} {\:}}\:\frac{\boldsymbol{\mathrm{x}}\left(\mathrm{1}+\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{cos}}\:\boldsymbol{\mathrm{x}}\right)−\boldsymbol{\mathrm{b}}\:\boldsymbol{\mathrm{sin}}\:\boldsymbol{\mathrm{x}}\:}{\boldsymbol{\mathrm{x}}^{\mathrm{3}} }=\mathrm{1}. \\ $$ Commented by mathmax by…
Question Number 84063 by niroj last updated on 09/Mar/20 $$ \\ $$$$\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\theta}\:\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{Mean}}\:\boldsymbol{\mathrm{Value}} \\ $$$$\:\boldsymbol{\mathrm{Theorem}}\:\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{h}}\right)=\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}}\right)+\boldsymbol{\mathrm{h}}\:\boldsymbol{\mathrm{f}}^{\:'} \:\left(\boldsymbol{\mathrm{x}}+\boldsymbol{\theta\mathrm{h}}\right)\:\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}}\right)=\:\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 84059 by niroj last updated on 09/Mar/20 $$ \\ $$$$\:\boldsymbol{\mathrm{Find}}\:\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}\:\boldsymbol{\mathrm{of}}\:\:\:\boldsymbol{\mathrm{x}}^{\boldsymbol{\mathrm{m}}} \boldsymbol{\mathrm{x}}^{\boldsymbol{\mathrm{n}}} \:=\left(\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}\right)^{\boldsymbol{\mathrm{m}}+\boldsymbol{\mathrm{n}}} . \\ $$ Commented by jagoll last updated on 09/Mar/20 $${x}^{{m}+{n}}…
Question Number 18470 by tawa tawa last updated on 22/Jul/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{partial}\:\mathrm{derivatives}\:\mathrm{for}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{Z}\:=\:\mathrm{3x}^{\mathrm{2}} \left(\mathrm{5x}\:+\:\mathrm{7y}\right)^{\mathrm{2}} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{Z}\:=\:\left(\mathrm{w}\:−\:\mathrm{x}\:−\:\mathrm{y}\right)^{\mathrm{2}} \:\left(\mathrm{3w}\:+\:\mathrm{2x}\:−\:\mathrm{4y}\right) \\ $$ Answered by ajfour last updated on…
Question Number 18469 by tawa tawa last updated on 22/Jul/17 $$\mathrm{Find}\:\mathrm{Z}_{\mathrm{x}} \:\mathrm{and}\:\mathrm{Z}_{\mathrm{y}} \:\mathrm{for}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the}\:\mathrm{functions}\:\mathrm{below} \\ $$$$\left(\mathrm{a}\right)\:\:\mathrm{Z}\:=\:\mathrm{8x}^{\mathrm{2}} \mathrm{y}\:+\:\mathrm{14xy}^{\mathrm{2}} \:+\:\mathrm{5y}^{\mathrm{2}} \mathrm{x}^{\mathrm{3}} \\ $$$$\left(\mathrm{b}\right)\:\:\mathrm{Z}\:=\:\mathrm{4x}^{\mathrm{3}} \mathrm{y}^{\mathrm{2}} \:+\:\mathrm{2x}^{\mathrm{2}} \mathrm{y}^{\mathrm{3}} \:−\:\mathrm{7xy}^{\mathrm{5}} \\…
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Question Number 18283 by tawa tawa last updated on 17/Jul/17 $$\mathrm{Given}:\:\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \\ $$$$\mathrm{Show}\:\mathrm{that},\:\:\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\:=\:\frac{\mathrm{xy}}{\mathrm{y}^{\mathrm{2}} \:+\:\mathrm{x}^{\mathrm{2}} } \\ $$ Terms of Service Privacy Policy…