Question Number 129988 by mnjuly1970 last updated on 21/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\:{nice}\:\:{calculus}\:… \\ $$$$\:\:{evaluate}:\: \\ $$$$\:\:\:\phi\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{dx}}{\left({x}−{x}^{\mathrm{3}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} }\:=? \\ $$$$ \\ $$ Answered by Dwaipayan…
Question Number 64295 by mathmax by abdo last updated on 16/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64287 by aliesam last updated on 16/Jul/19 Commented by mathmax by abdo last updated on 16/Jul/19 $${R}^{'} \left({t}\right)\:=\frac{\mathrm{15}.\mathrm{0},\mathrm{01}\:{e}^{−\mathrm{0},\mathrm{01}{t}} \left(\mathrm{1}+\mathrm{1},\mathrm{5}{e}^{−\mathrm{0},\mathrm{01}{t}} \right)−\mathrm{15}\left(\mathrm{1}−{e}^{−\mathrm{0},\mathrm{01}{t}} \right)\left(−\mathrm{1},\mathrm{5}\right)\mathrm{0},\mathrm{01}\:{e}^{−\mathrm{0},\mathrm{01}{t}} }{\left(\mathrm{1}+\mathrm{1},\mathrm{5}\:{e}^{−\mathrm{0},\mathrm{01}{t}} \right)^{\mathrm{2}}…
Question Number 129815 by stelor last updated on 19/Jan/21 $$\mathrm{Calculer}\:\mathrm{les}\:\mathrm{d}\acute {\mathrm{e}riv}\acute {\mathrm{e}es}\:\mathrm{n}-\mathrm{i}\grave {\mathrm{e}mes}\:\mathrm{en}\:\mathrm{0}\:\mathrm{de}\: \\ $$$$\mathrm{la}\:\mathrm{fonction}\:\mathrm{d}\acute {\mathrm{e}finie}\:\mathrm{par}\:\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{1}+\mathrm{x}^{\mathrm{4}} } \\ $$ Answered by mathmax by abdo…
Question Number 129806 by mnjuly1970 last updated on 19/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\:{nice}\:\:\:{calculus}\:… \\ $$$$\:\:\:{please}\:\:{prove}\:{that}\::: \\ $$$$\:\:\:\:\Phi\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{Arctan}\left({x}\right)}{\mathrm{1}+{x}}\:{dx}=\frac{\pi}{\mathrm{8}}\:{log}\left(\mathrm{2}\right)\:… \\ $$$$ \\ $$ Answered by Dwaipayan Shikari last…
Question Number 129805 by mnjuly1970 last updated on 19/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:…\:{nice}\:\:\:\:\:\:\:{calculus}\:… \\ $$$$\:{please}\:{calculate}\:::: \\ $$$$\:\:\:\:\:\mathrm{I}:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \left\{\frac{\mathrm{1}}{\:\sqrt[{\mathrm{6}}]{{x}}}\:\right\}{dx} \\ $$$$\:\:\:\:{notice}:\:\left\{{x}\right\}\:{is}\:{the}\:{fractionl}\:{of}\:''\:{x}\:''. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:……………. \\ $$ Answered by mindispower…
Question Number 129758 by I want to learn more last updated on 18/Jan/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{derivatives}\:\mathrm{of}\:\:\:\:\mathrm{log}_{\mathrm{e}} \left(\mathrm{6x}\:+\:\mathrm{8}\right)^{\mathrm{5}} \\ $$ Commented by Dwaipayan Shikari last updated on 18/Jan/21…
Question Number 64074 by mmkkmm000m last updated on 12/Jul/19 $${by}\:{using}\:{laplase}\:{transform}\:{find}\:{laplase}\left({tan}\left({t}\right)\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64060 by mmkkmm000m last updated on 12/Jul/19 $$\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{2}} +\mathrm{25}/\left({x}+\mathrm{3}\right)^{\mathrm{2}} =\sqrt{\mathrm{2}} \\ $$ Commented by MJS last updated on 12/Jul/19 $$\mathrm{Sir}\:\mathrm{would}\:\mathrm{you}\:\mathrm{mind}\:\mathrm{using}\:\mathrm{smaller}\:\mathrm{font}\:\mathrm{size}\:\mathrm{as}\:\mathrm{it}'\mathrm{s}\:\mathrm{hard}\:\mathrm{to}\:\mathrm{overview}\:\mathrm{the}\:\mathrm{forum}\:\mathrm{like}\:\mathrm{this} \\ $$ Terms…
Question Number 129545 by mnjuly1970 last updated on 16/Jan/21 Answered by mindispower last updated on 16/Jan/21 $$=\int_{\mathrm{0}} ^{\infty} \frac{{sin}^{\mathrm{2}} \left({x}\right)}{{x}^{\mathrm{2}} }−\int_{\mathrm{0}} ^{\infty} \frac{{sin}^{\mathrm{2}} \left({x}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx}…