Question Number 147748 by Odhiambojr last updated on 23/Jul/21 $${prove}\:{that}\:{curves}\:{x}^{\mathrm{2}\:} −{y}^{\mathrm{2}} =\mathrm{3}\:{and} \\ $$$$\:{xy}=\mathrm{2}\:{intersect}\:{at}\:{the}\:{right}\:{angle}\: \\ $$$$ \\ $$ Commented by Olaf_Thorendsen last updated on 23/Jul/21…
Question Number 147713 by Odhiambojr last updated on 22/Jul/21 $${Find}\:{a}\:{point}\:{on}\:{the}\:{curve}\:{y}=\sqrt{{x}} \\ $$$${where}\:{the}\:{tangent}\:{makes}\:{an}\:{angle}\: \\ $$$$\mathrm{45}°\:{with}\:{the}\:{positive}\:{x}-{axis} \\ $$ Answered by Olaf_Thorendsen last updated on 22/Jul/21 $$\frac{{dy}}{{dx}}\:=\:\mathrm{tan}\left(\theta\left({x}\right)\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}\sqrt{{x}}} \\…
Question Number 82109 by jagoll last updated on 18/Feb/20 $${what}\:{is}\:{solution} \\ $$$$\frac{{dy}}{{dx}}\:=\:\mathrm{sin}\:\left({x}+{y}\right) \\ $$ Commented by mr W last updated on 18/Feb/20 $${u}={x}+{y} \\ $$$${y}={u}−{x}…
Question Number 147609 by 0731619 last updated on 22/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 82059 by jagoll last updated on 18/Feb/20 $${what}\:{is}\:{derivative}\:{of}\:\:{h}\:=\:\sqrt{{ln}\left({x}\right)} \\ $$$${by}\:{first}\:{principle}\:{method}\: \\ $$ Answered by Henri Boucatchou last updated on 18/Feb/20 $$\frac{\mathrm{dh}\left(\mathrm{x}\right)}{\mathrm{dx}}=\frac{\mathrm{d}\sqrt{\mathrm{lnx}}}{\mathrm{dx}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\frac{\mathrm{dlnx}}{\mathrm{dx}}}{\mathrm{2}\sqrt{\mathrm{lnx}}}…
Question Number 82018 by TawaTawa last updated on 17/Feb/20 $$\mathrm{Differentiate}\:\:\:\:\:\mathrm{y}\:\:=\:\:\mathrm{2}^{\mathrm{x}} \:\:\:\:\mathrm{from}\:\mathrm{the}\:\mathrm{first}\:\mathrm{principle}. \\ $$ Commented by john santu last updated on 17/Feb/20 $${ln}\:{y}\:=\:{x}\:{ln}\:\mathrm{2} \\ $$$$\underset{{h}\rightarrow\mathrm{0}} {\mathrm{lim}}\:{ln}\left({y}\right)\:\:=\:\underset{{h}\rightarrow\mathrm{0}}…
Question Number 81954 by Cmr 237 last updated on 16/Feb/20 $$\left.\:{soit}\:\alpha\in\right]\mathrm{0};\pi\left[.\:{determiner}:\right. \\ $$$$\left.\mathrm{1}\right){le}\:{module}\:{et}\:{l}'{argument}\:{de}: \\ $$$$\left.\boldsymbol{{a}}\left.\right)\mathrm{1}−\boldsymbol{{e}}^{\boldsymbol{{i}}\alpha} ,\boldsymbol{{b}}\right)\mathrm{1}+\boldsymbol{{e}}^{\boldsymbol{{i}\alpha}} \\ $$$$\left.\mathrm{2}\right)\boldsymbol{{deduire}}\:\boldsymbol{{le}}\:\boldsymbol{{module}}\:\boldsymbol{{et}}\:\boldsymbol{{l}}'\boldsymbol{{argument}}\:\boldsymbol{{de}} \\ $$$$\left.\:\left.\boldsymbol{{a}}\right)\:\frac{\mathrm{1}−\boldsymbol{{e}}^{\boldsymbol{{i}}\alpha} }{\mathrm{1}+{e}^{{i}\alpha} },\:{b}\right)\left(\mathrm{1}−{e}^{{i}\alpha} \right)\left(\mathrm{1}+{e}^{{i}\alpha} \right) \\…
Question Number 147474 by mnjuly1970 last updated on 21/Jul/21 Answered by mindispower last updated on 21/Jul/21 $$\frac{\mathrm{1}}{\mathrm{2}{a}}\left(\underset{{n}\geqslant−\infty} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{4}{n}−{a}}−\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{4}{n}+{a}}\right)=\underset{{n}\geqslant−\infty} {\sum}\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{16}{n}^{\mathrm{2}} −{a}^{\mathrm{2}} }={f}\left({a}\right)…
Question Number 147411 by mnjuly1970 last updated on 20/Jul/21 Answered by mnjuly1970 last updated on 20/Jul/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\::\overset{\sqrt{{x}}\::=\:{y}} {=}\:\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{2}{y}\:{dy}}{\mathrm{1}+{e}^{\:{y}} }\:=\mathrm{2}\:\int_{\mathrm{0}} ^{\:\infty} \frac{{ydy}}{\mathrm{1}+{e}^{\:{y}} } \\…
Question Number 81835 by M±th+et£s last updated on 15/Feb/20 Commented by M±th+et£s last updated on 15/Feb/20 $${hn}:\:{harmonic}\:{number} \\ $$ Terms of Service Privacy Policy Contact:…