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Category: Differentiation

Question-146602

Question Number 146602 by mnjuly1970 last updated on 14/Jul/21 Answered by qaz last updated on 15/Jul/21 1cos(12x)2sinxdx=sin2(6x)sinxdx=4[sin(3x)cos(3x)]2sinxdx$$=\mathrm{4}\int\frac{\left[\left(\mathrm{3sin}\:\mathrm{x}−\mathrm{4sin}\:^{\mathrm{3}} \mathrm{x}\right)\left(\mathrm{4cos}\:^{\mathrm{3}} \mathrm{x}−\mathrm{3cos}\:\mathrm{x}\right)\right]^{\mathrm{2}}…