Question Number 72877 by mhmd last updated on 04/Nov/19 $${by}\:{using}\:{theorem}\:{demwover}\:{find}\:\:{x}^{\mathrm{4}} =\mathrm{1}? \\ $$$${pleas}\:{sir}\:{help}\:{me} \\ $$ Commented by mathmax by abdo last updated on 04/Nov/19 $${roots}\:{at}\:{C}\:\:\:\:{x}={z}={r}\:{e}^{{i}\theta}…
Question Number 138377 by mnjuly1970 last updated on 13/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:……\:{advanced}\:…\:…\:…\:{calculus}…… \\ $$$$\:\:\:{evaluate}:::: \\ $$$$\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\infty} \frac{{ln}\left({x}\right)}{\:\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} }\:.\left(\mathrm{2}+{x}\right)}\:{dx}=?? \\ $$$$\:\: \\ $$ Terms of…
Question Number 7294 by Tawakalitu. last updated on 21/Aug/16 $${If}\:{a}\:{polynomial}\:{p}\left({x}\right)\:{satisfies}\:{the}\:{identity} \\ $$$$ \\ $$$${x}^{\mathrm{2015}} \:+\:{x}^{\mathrm{2014}} \:+\:{x}^{\mathrm{2013}} \:+\:\mathrm{1}\:=\:\left({x}^{\mathrm{3}} \:+\:{x}^{\mathrm{2}} \:+\:{x}\:+\:\mathrm{1}\right){p}\left({x}\right) \\ $$$$ \\ $$$${Find}\:\:{p}\left(−\mathrm{1}\right) \\ $$…
Question Number 72823 by Raxreedoroid last updated on 03/Nov/19 $$\mathrm{What}\:\mathrm{is}\:\mathrm{derivative}\:\mathrm{for}\:\mathrm{this}\:\mathrm{function} \\ $$$$\: \\ $$$${a}×{b}^{{x}−\mathrm{1}} ×{c}^{\frac{\mathrm{1}}{\mathrm{2}}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)} ×{d}^{\frac{\mathrm{1}}{\mathrm{6}}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)\left({x}−\mathrm{3}\right)} \\ $$ Answered by mind is power last updated…
Question Number 138348 by EnterUsername last updated on 12/Apr/21 Commented by EnterUsername last updated on 12/Apr/21 Image courtesy of Anna Lachowska. Terms of Service Privacy…
Question Number 7265 by 2402@gmail.com last updated on 20/Aug/16 $${Q}\mathrm{1}.\:{A}\:{balloon}\:{in}\:{the}\:{shape}\:{of}\:{cone}\:{surrmo} \\ $$$$\:\:\:\:\:\:\:\:\:\:{surmounted}\:{by}\:{hemispherical} \\ $$$$\:\:\:\:\:\:\:\:\:{top}\:.\:{the}\:{daimeter}\:{of}\:{balloon}\:{is} \\ $$$$\:\:\:\:\:\:\:{equal}\:{to}\:{hieght}\:{of}\:{cone}\:.\:{find}\:{the} \\ $$$$\:\:\:\:\:{rate}\:{of}\:{change}\:{of}\:{volume}\:{of}\:{the} \\ $$$$\:\:\:{balloone}\:{with}\:{respect}\:{to}\:{its}\:{total} \\ $$$$\:\:\:\:{height}\:\:{h}\:. \\ $$ Commented…
Question Number 7245 by 2402@gmail.com last updated on 18/Aug/16 $${Q}\mathrm{1}.{if}\:{y}^{\mathrm{1}/{n}} +{y}^{−\mathrm{1}/{n}} \:=\mathrm{2}\:{find}\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:. \\ $$$$ \\ $$$$ \\ $$ Commented by Yozzia last updated…
Question Number 138278 by 676597498 last updated on 11/Apr/21 Answered by TheSupreme last updated on 12/Apr/21 $$ \\ $$$$\mathrm{6}{x}=\mathrm{4}\left({mod}\mathrm{5}\right) \\ $$$$\mathrm{6}{x}=\mathrm{2}\left({mod}\mathrm{7}\right) \\ $$$$ \\ $$$$\mathrm{5}{y}_{\mathrm{2}}…
Question Number 72724 by rajesh4661kumar@gmail.com last updated on 01/Nov/19 Commented by kaivan.ahmadi last updated on 01/Nov/19 $$\frac{\pi}{\mathrm{2}}<{x}_{\mathrm{1}} <{x}_{\mathrm{2}} <\pi\Rightarrow\mathrm{0}<\mid{cosx}_{\mathrm{2}} \mid<\mid{cosx}_{\mathrm{1}} \mid<\mathrm{1}\Rightarrow \\ $$$${log}\mid{cosx}_{\mathrm{2}} \mid<{log}\mid{cosx}_{\mathrm{1}} \mid…
Question Number 138209 by 676597498 last updated on 11/Apr/21 $${I}_{{n}} =\int_{\mathrm{0}} ^{\:\mathrm{1}} {x}^{{n}} \sqrt{{x}^{\mathrm{2}} +\mathrm{1}}{dx} \\ $$$${find}\:{reduction}\:{formula} \\ $$ Commented by Dwaipayan Shikari last updated…