Question Number 5903 by sanusihammed last updated on 04/Jun/16 $${if}\:\:\:{x}^{{y}\:} \:=\:\:{e}^{\left({x}\:−\:{y}\right)} \\ $$$$ \\ $$$${find}\:\:{dy}/{dx} \\ $$$$ \\ $$$${please}\:{help}. \\ $$ Answered by uchechukwu okorie…
Question Number 5874 by sanusihammed last updated on 02/Jun/16 $${Prove}\:{the}\:{identity}.\: \\ $$$${cosh}^{−\mathrm{1}} \left({x}\right)\:=\:{sinh}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{{x}}\right) \\ $$$$ \\ $$$${please}\:{help}. \\ $$ Answered by Yozzii last updated…
Question Number 5873 by sanusihammed last updated on 02/Jun/16 $${Differentiate}\:\:\:{cosh}^{−\mathrm{1}} \left({x}^{\mathrm{2}} \:+\:\mathrm{1}\right)\:\frac{{dy}}{{dx}}.\:\:\:{if}\:{the}\:{given}\:{function}\:{is}\: \\ $$$${y}\:=\:{sinh}^{−\mathrm{1}} \left[{coth}\left({x}^{\mathrm{2}} \right)\right] \\ $$$$ \\ $$$${Please}\:{help}. \\ $$ Terms of Service…
Question Number 5866 by sanusihammed last updated on 02/Jun/16 $${Solve}\:{integral}\:{of}\:\:\:{sec}\left({x}\right){dx}\:\:.\:\:{given}\:{that}\:\:{t}\:=\:{tan}\left(\frac{{x}}{\mathrm{2}}\right) \\ $$ Answered by Yozzii last updated on 02/Jun/16 $${Let}\:{t}={tan}\mathrm{0}.\mathrm{5}{x}\Rightarrow{dt}=\mathrm{0}.\mathrm{5}{sec}^{\mathrm{2}} \mathrm{0}.\mathrm{5}{xdx} \\ $$$${dx}=\frac{\mathrm{2}{dt}}{\mathrm{1}+{t}^{\mathrm{2}} } \\…
Question Number 5855 by sanusihammed last updated on 01/Jun/16 $${If}\:\:\:{xy}^{\mathrm{3}\:} \:=\:\:{sin}\left({xy}\right) \\ $$$$ \\ $$$${find}\:\:\:\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} } \\ $$$$ \\ $$$${Please}\:{i}\:{need}\:{help}.\:{thanks}\:{for}\:{your}\:{effort} \\ $$ Answered by…
Question Number 71371 by rajesh4661kumar@gmail.com last updated on 14/Oct/19 Commented by prakash jain last updated on 15/Oct/19 $${x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{2}{y}−\mathrm{23}=\mathrm{0} \\ $$$$\left({x}−\mathrm{1}\right)^{\mathrm{2}} +\left({y}+\mathrm{1}\right)^{\mathrm{2}} =\mathrm{25} \\…
Question Number 5734 by sanusihammed last updated on 25/May/16 $${Please}\:{show}\:{me}\:{an}\:{approach}\:{to}\:{solve}\:{this}… \\ $$$$ \\ $$$$\mathrm{2}^{{x}} \:=\:\mathrm{4}{x} \\ $$$$ \\ $$$${Find}\:{the}\:{value}\:{of}\:{x}\: \\ $$ Answered by prakash jain…
Question Number 5715 by sanusihammed last updated on 24/May/16 $${Differentiate}\:\:\:{x}^{{x}} \:\:\:{from}\:{the}\:{first}\:{principle}. \\ $$$$ \\ $$$${please}\:{help} \\ $$ Answered by Yozzii last updated on 25/May/16 $${Let}\:{y}={x}^{{x}}…
Question Number 5614 by Rasheed Soomro last updated on 22/May/16 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{cordinates}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two}\:\mathrm{points} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{curve}\:\mathrm{y}=\mathrm{4}−\mathrm{x}^{\mathrm{2}} \:\:\mathrm{whose}\:\mathrm{tangents} \\ $$$$\mathrm{pass}\:\mathrm{through}\:\mathrm{the}\:\mathrm{point}\:\left(−\mathrm{1},\:\mathrm{7}\right)\:. \\ $$ Commented by Rasheed Soomro last updated on…
Question Number 5615 by Rasheed Soomro last updated on 22/May/16 $$\mathrm{The}\:\mathrm{tangent}\:\mathrm{at}\:\mathrm{the}\:\mathrm{point}\:\mathrm{P}\left({a},{b}\right)\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{curve}\:\:\mathrm{y}=\frac{{ab}}{{x}}\:\:\mathrm{meets}\:\mathrm{the}\:\mathrm{x}-\mathrm{axis}\:\mathrm{and}\:\mathrm{y}-\mathrm{axis} \\ $$$$\mathrm{at}\:\mathrm{Q}\:\mathrm{and}\:\mathrm{R}\:\mathrm{respectively}.\:\mathrm{Show}\:\mathrm{that} \\ $$$$\mathrm{PQ}=\mathrm{RP}\:. \\ $$ Commented by prakash jain last updated…