Question Number 132104 by mnjuly1970 last updated on 11/Feb/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\:{calculus}\:\left(\mathrm{1}\right)… \\ $$$$\:\:{if}\:\:{y}=\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{{sin}\left({x}\right)+{cos}\left({x}\right)}}\:\:{then}\:: \\ $$$$\:\:\:\:\mathrm{3}{y}''−\mathrm{12}\left({y}'\right)^{\mathrm{2}} −{y}^{\mathrm{2}} =\:??? \\ $$$$\:\:\:\:\:……… \\ $$ Answered by mnjuly1970 last updated…
Question Number 132076 by liberty last updated on 11/Feb/21 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{function}\:\mathrm{f}\left({x}\right)=\int_{\mathrm{0}} ^{\:{x}} \left(\mathrm{1}+{t}^{\mathrm{3}} \right)^{−\mathrm{1}/\mathrm{2}} {dt}. \\ $$$$\mathrm{If}\:\mathrm{h}\left({x}\right)\:\mathrm{is}\:\mathrm{the}\:\mathrm{inverse}\:\mathrm{of}\:\mathrm{f}\left({x}\right)\:\mathrm{and}\:\mathrm{h}'\left({x}\right) \\ $$$$\mathrm{is}\:\mathrm{derivative}\:\mathrm{of}\:\mathrm{h}\left({x}\right).\:\mathrm{Find}\:\mathrm{the}\: \\ $$$$\mathrm{value}\:\mathrm{of}\:\frac{\mathrm{h}''\left({x}\right)}{\left(\mathrm{h}\left(\mathrm{x}\right)\right)^{\mathrm{2}} }\:. \\ $$$$ \\ $$…
Question Number 66498 by miracle wokama last updated on 16/Aug/19 Commented by MJS last updated on 16/Aug/19 $$\mathrm{too}\:\mathrm{complicated} \\ $$$$\mathrm{it}'\mathrm{s}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{see}\:\mathrm{that}\:{f}'\left(\mathrm{0}\right)=\mathrm{1}\:\mathrm{and}\:{f}'\left(\mathrm{1}\right)=\mathrm{100} \\ $$ Commented by mathmax…
Question Number 923 by 123456 last updated on 25/Apr/15 $${f}\left({x},{y},{z}\right)={x}+{y}+{z} \\ $$$$\boldsymbol{{g}}\left({x},{y},{z}\right)=\left({x},{y},{z}\right) \\ $$$$\boldsymbol{{h}}\left({x},{y},{z}\right)=\boldsymbol{{g}}\left({x},{y},{z}\right)−\bigtriangledown{f}\left({x},{y},{z}\right)=??? \\ $$$$\bigtriangledown\centerdot\boldsymbol{{h}}\left({x},{y},{z}\right)=? \\ $$$$\bigtriangledown×\boldsymbol{{h}}\left({x},{y},{z}\right)=??? \\ $$ Answered by 2closedStringsMeet last updated…
Question Number 131965 by liberty last updated on 10/Feb/21 Commented by liberty last updated on 10/Feb/21 Commented by TheSupreme last updated on 10/Feb/21 $${T}={t}_{\mathrm{1}} +{t}_{\mathrm{2}}…
Question Number 131960 by liberty last updated on 10/Feb/21 Answered by mr W last updated on 10/Feb/21 $${r}^{\mathrm{2}} +{h}^{\mathrm{2}} =\left(\sqrt{\mathrm{3}}\right)^{\mathrm{2}} \:\Rightarrow{r}^{\mathrm{2}} =\mathrm{3}−{h}^{\mathrm{2}} \\ $$$${V}=\frac{\pi}{\mathrm{3}}{r}^{\mathrm{2}} {h}=\frac{\pi}{\mathrm{3}}\left(\mathrm{3}−{h}^{\mathrm{2}}…
Question Number 131887 by Algoritm last updated on 09/Feb/21 Answered by SEKRET last updated on 09/Feb/21 $$\:\boldsymbol{\mathrm{Leybnist}}\:\:\:\boldsymbol{\mathrm{formula}} \\ $$$$\:\:\boldsymbol{\mathrm{u}}=\:\boldsymbol{\mathrm{e}}^{−\mathrm{2}\boldsymbol{\mathrm{x}}} \:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{u}}^{\boldsymbol{\mathrm{n}}} =\left(−\mathrm{2}\right)^{\boldsymbol{\mathrm{n}}} \centerdot\boldsymbol{\mathrm{e}}^{−\mathrm{2}\boldsymbol{\mathrm{x}}} \\ $$$$\:\boldsymbol{\mathrm{v}}=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}−\boldsymbol{\mathrm{x}}}}\:\:\:\:\:\:\boldsymbol{\mathrm{v}}^{\boldsymbol{\mathrm{n}}} =\frac{\left(\mathrm{2}\boldsymbol{\mathrm{n}}−\mathrm{1}\right)!!}{\mathrm{2}^{\boldsymbol{\mathrm{n}}}…
Question Number 131827 by Salman_Abir last updated on 09/Feb/21 Answered by liberty last updated on 09/Feb/21 $$\left.\:=\:\mathrm{ln}\:\mid\mathrm{tan}\:\mathrm{x}\mid\:\right]_{\frac{\pi}{\mathrm{4}}} ^{\frac{\pi}{\mathrm{3}}} \:=\:\mathrm{ln}\:\mid\mathrm{tan}\:\frac{\pi}{\mathrm{3}}\mid−\mathrm{ln}\:\mid\mathrm{tan}\:\frac{\pi}{\mathrm{4}}\mid \\ $$$$\:=\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\left(\mathrm{3}\right) \\ $$ Terms of…
Question Number 66256 by Mikael last updated on 11/Aug/19 $${Find}\:{all}\:{points}\:\left({a},\:{b}\right)\:{of}\:\mathbb{R}^{\mathrm{2}} \:{such}\:{that}\: \\ $$$${through}\:\left({a},\:{b}\right)\:{pass}\:{two}\:{tangent}\:{lines} \\ $$$${to}\:{the}\:{graph}\:{of}\:{f}\left({x}\right)={x}^{\mathrm{2}} . \\ $$ Commented by kaivan.ahmadi last updated on 11/Aug/19…
Question Number 131775 by Raxreedoroid last updated on 08/Feb/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{derivative}\:\mathrm{of} \\ $$$${g}\left({x}\right)=\int_{\mathrm{tan}\:{x}} ^{\:{x}^{\mathrm{2}} } \frac{\mathrm{1}}{\:\sqrt{\mathrm{2}+{t}^{\mathrm{4}} }}\:{dt} \\ $$ Answered by bemath last updated on 08/Feb/21…