Question Number 126641 by TITA last updated on 22/Dec/20 Commented by TITA last updated on 22/Dec/20
Question Number 126635 by BHOOPENDRA last updated on 22/Dec/20 Answered by Ar Brandon last updated on 22/Dec/20 $$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} =\mathrm{r}^{\mathrm{2}} \mathrm{cos}^{\mathrm{2}} \theta\mathrm{cos}^{\mathrm{2}} \phi+\mathrm{r}^{\mathrm{2}} \mathrm{cos}^{\mathrm{2}}…
Question Number 126631 by mnjuly1970 last updated on 23/Dec/20
Question Number 126605 by bramlexs22 last updated on 22/Dec/20
Question Number 126524 by rs4089 last updated on 21/Dec/20 Answered by Olaf last updated on 21/Dec/20
Question Number 192054 by cortano12 last updated on 07/May/23
Question Number 126478 by BHOOPENDRA last updated on 20/Dec/20
Question Number 126476 by mnjuly1970 last updated on 20/Dec/20
Question Number 126440 by mnjuly1970 last updated on 20/Dec/20
Question Number 191859 by mathlove last updated on 02/May/23 Commented by mr W last updated on 03/May/23