Question Number 209041 by alcohol last updated on 30/Jun/24 Commented by alcohol last updated on 30/Jun/24 $${find}\:{r} \\ $$ Commented by mr W last updated…
Question Number 208976 by efronzo1 last updated on 30/Jun/24 Answered by mr W last updated on 30/Jun/24 $${say}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={u},\:{xy}={v} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} \geqslant\mathrm{2}\sqrt{{x}^{\mathrm{2}} {y}^{\mathrm{2}}…
Question Number 208908 by alcohol last updated on 26/Jun/24 $${I}\left({a},{b}\right)\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} {t}^{{a}} \left(\mathrm{1}−{t}\right)^{{b}} {dt} \\ $$$${Note}\::\:{I}\left({a},{b}\right)\:=\:\frac{{a}}{{b}+\mathrm{1}}{I}\left({a}−\mathrm{1},{b}+\mathrm{1}\right) \\ $$$${show}\:{that} \\ $$$$\bullet\:{I}\left({a}+\mathrm{1},\:{b}\right)\:+\:{I}\left({a},{b}+\mathrm{1}\right)\:=\:{I}\left({a},\:{b}\right) \\ $$$$\bullet\:{find}\:{B}\left({a}+\mathrm{1},\:{b}+\mathrm{1}\right)\:{interms}\:{of}\:{B}\left({a},{b}\right) \\ $$$$\bullet\:{use}\:{I}\left({a},{b}\right)\:=\:{I}\left({b},{a}\right)\:{and}\:{deduce}\:{I}\left(\frac{\mathrm{5}}{\mathrm{2}},\frac{\mathrm{3}}{\mathrm{2}}\right) \\…
Question Number 208855 by efronzo1 last updated on 25/Jun/24 Answered by mr W last updated on 25/Jun/24 $${let}\:{t}=\mathrm{1}+\mid{x}\mid\geqslant\mathrm{1} \\ $$$$\frac{\mathrm{2024}^{−{t}} −\lambda}{\mathrm{2024}^{−{t}} −\lambda^{−\mathrm{1}} }=\lambda\:\mathrm{2024}^{{t}} \\ $$$$\mathrm{2024}^{−{t}}…
Question Number 208553 by efronzo1 last updated on 18/Jun/24 $$\:\:\:\cancel{ } \\ $$ Answered by mr W last updated on 18/Jun/24 $${due}\:{to}\:{symmetry} \\ $$$${y}={x}\:\Rightarrow\mathrm{3}{x}^{\mathrm{2}} =\mathrm{1}\:\Rightarrow{x}=\pm\frac{\sqrt{\mathrm{3}}}{\mathrm{3}}…
Question Number 208499 by efronzo1 last updated on 17/Jun/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 207954 by solihin last updated on 01/Jun/24 $$\:\underline{\boldsymbol{{x}}} \\ $$ Commented by MathematicalUser2357 last updated on 02/Jun/24 $${I}\:{see}\:\underline{\boldsymbol{{x}}}\:{in}\:{tinku}\:{tara} \\ $$ Answered by AliJumaa…
Question Number 207175 by MATHEMATICSAM last updated on 08/May/24 $$\mathrm{If}\:{x}^{{m}} .{y}^{{n}} \:=\:\left({x}\:+\:{y}\right)^{{m}\:+\:{n}} \:\mathrm{then}\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:=\:? \\ $$ Answered by som(math1967) last updated on 08/May/24 $${lnx}^{{m}}…
Question Number 207122 by MATHEMATICSAM last updated on 07/May/24 $$\mathrm{If}\:{e}^{{y}} \left({x}\:+\:\mathrm{1}\right)\:=\:\mathrm{1}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:=\:\left(\frac{{dy}}{{dx}}\right)^{\mathrm{2}} . \\ $$ Answered by BaliramKumar last updated on 07/May/24…
Question Number 207109 by MATHEMATICSAM last updated on 06/May/24 $$\mathrm{If}\:{y}\:=\:\left(\mathrm{1}\:+\:{x}\right)\left(\mathrm{1}\:+\:{x}^{\mathrm{2}} \right)\left(\mathrm{1}\:+\:{x}^{\mathrm{4}} \right)\:….\:\left(\mathrm{1}\:+\:{x}^{\mathrm{2}{n}} \right) \\ $$$$\mathrm{then}\:\mathrm{find}\:\frac{{dy}}{{dx}}\:\mathrm{at}\:{x}\:=\:\mathrm{0}. \\ $$ Answered by Berbere last updated on 06/May/24 $${y}\left({x}\right)=\left(\mathrm{1}+{x}\right)\underset{{k}=\mathrm{1}}…