Question Number 118304 by mnjuly1970 last updated on 16/Oct/20 $$\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\:\underset{\blacktrinagledown} {\overset{\blacktrinagledown} {\blacklozenge}}\mathscr{A}{dvanced}\:\:{calculus}\underset{\blacktrinagledown} {\overset{\blacktrinagledown} {\blacklozenge}}\:… \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{prove}\:\:{that}\::: \\ $$$$\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\mathrm{3}^{{n}} {n}^{\mathrm{3}}…
Question Number 118210 by bemath last updated on 16/Oct/20 Answered by john santu last updated on 16/Oct/20 $${Reduces}\:{the}\:{equation}\:{of}\:{the}\:{cylinder} \\ $$$${to}\:{r}^{\mathrm{2}} =\mathrm{2}{r}\:\mathrm{cos}\:\theta\:{or}\:{r}\:=\:\mathrm{2cos}\:\theta,\:{in}\:\theta\:\in\:\left[\mathrm{0},\pi\:\right] \\ $$$${The}\:{volume}\:{equals}\: \\ $$$$\int\int\left(\mathrm{8}{x}^{\mathrm{2}}…
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Question Number 183711 by Michaelfaraday last updated on 29/Dec/22 Commented by Matica last updated on 29/Dec/22 $${to}\:{mathematize} \\ $$ Answered by HeferH last updated on…
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Question Number 118004 by TANMAY PANACEA last updated on 14/Oct/20 $${find}\:\:{value}\:{of}\:{tan}\mathrm{46}^{\mathrm{0}} \:{using}\:{calculus} \\ $$ Answered by mr W last updated on 14/Oct/20 $$\mathrm{46}°=\mathrm{45}°+\mathrm{1}°=\frac{\pi}{\mathrm{4}}+\frac{\pi}{\mathrm{180}} \\ $$$$\mathrm{tan}\:\mathrm{46}°=\frac{\mathrm{1}+\mathrm{tan}\:\frac{\pi}{\mathrm{180}}}{\mathrm{1}−\mathrm{tan}\:\frac{\pi}{\mathrm{180}}}…
Question Number 117953 by mnjuly1970 last updated on 14/Oct/20 $$\:\:\:\:\:\:\:\:\:…\:\:\blacktriangleleft{nice}\:\:{integral}\blacktriangleright… \\ $$$$\:\:\:\:{please}\:\:{prove}\:: \\ $$$$ \\ $$$$\:\:\Omega=\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} {ln}^{\mathrm{2}} \left({cot}\left({x}\right)\right){dx}\:=\frac{\pi^{\mathrm{3}} }{\mathrm{8}}\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:…\spadesuit{m}.{n}.\mathrm{1070}\spadesuit… \\ $$ Answered…
Question Number 183447 by greougoury555 last updated on 26/Dec/22 $$\:\begin{cases}{{y}=\mathrm{sec}\:^{{n}} \theta−\mathrm{cos}\:^{{n}} \theta}\\{{x}=\mathrm{sec}\:\theta−\mathrm{cos}\:\theta}\end{cases} \\ $$$$\:{xy}\:'+\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right){y}''\:=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 117704 by bemath last updated on 13/Oct/20 $$\mathrm{Given}\:\mathrm{a}\:\mathrm{function}\:\psi:\mathbb{R}\rightarrow\mathbb{R} \\ $$$$\mathrm{with}\:\psi\left(\theta\right)\:=\:\theta^{\mathrm{2}} −\mathrm{x}^{\mathrm{2}} .\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value} \\ $$$$\mathrm{of}\:\frac{\mathrm{d}^{\mathrm{2}} \psi\left(\theta\right)}{\mathrm{dx}^{\mathrm{2}} }\:\:\mathrm{when}\:\theta=\mathrm{8} \\ $$ Commented by prakash jain last…