Question Number 52124 by 786786AM last updated on 03/Jan/19 $$\mathrm{The}\:\mathrm{curve}\:\mathrm{y}\:=\:\mathrm{ax}\:+\:\frac{\mathrm{b}}{\mathrm{2x}−\:\mathrm{1}}\:\mathrm{has}\:\mathrm{the}\:\mathrm{stationary}\:\mathrm{point}\:\mathrm{at}\:\:\left(\mathrm{2},\:\mathrm{7}\right)\:.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{a}\:\mathrm{and}\:\mathrm{b}\:. \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 03/Jan/19 $$\mathrm{2}{xy}−{y}=\mathrm{2}{ax}^{\mathrm{2}} −{ax}+{b} \\ $$$${partial}\:{derivative}\:{w}.{r}.{t}\:{x} \\ $$$$\mathrm{2}{y}−\mathrm{0}=\mathrm{4}{ax}−{a}…
Question Number 117557 by abdullahquwatan last updated on 12/Oct/20 $$\mathrm{second}\:\mathrm{derivative} \\ $$$${x}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} =\mathrm{5} \\ $$ Answered by Dwaipayan Shikari last updated on 12/Oct/20 $$\mathrm{2}{x}+\mathrm{6}{y}\frac{{dy}}{{dx}}=\mathrm{0}\Rightarrow\frac{{dy}}{{dx}}=−\frac{{x}}{\mathrm{3}{y}}…
Question Number 52006 by peter frank last updated on 01/Jan/19 $${Differentiate}\:\mathrm{sin}^{−\mathrm{1}} \left[\frac{\mathrm{ln}\:{x}}{\mathrm{cos}\:{x}}\right] \\ $$$${with}\:{respect}\:{to}\:\mathrm{tan}\:{x}^{\mathrm{2}} \\ $$ Commented by MJS last updated on 02/Jan/19 $$\mathrm{I}\:\mathrm{get}\:\left(\mathrm{with}\:\mathrm{no}\:\mathrm{respect}\:\mathrm{to}\:\mathrm{anything}\right) \\…
Question Number 117486 by Canovas last updated on 12/Oct/20 Answered by john santu last updated on 12/Oct/20 $$\frac{{dy}}{{dx}}\:=\:\mathrm{2}{x}.\left(\mathrm{2}^{{y}} \right)+{x}^{\mathrm{2}} .\mathrm{ln}\:\left(\mathrm{2}\right).\mathrm{2}^{{y}} \:\frac{{dy}}{{dx}} \\ $$$$\left(\mathrm{1}−\mathrm{ln}\:\left(\mathrm{2}\right){x}^{\mathrm{2}} .\mathrm{2}^{{y}} \right)\frac{{dy}}{{dx}}\:=\:\mathrm{2}{x}.\mathrm{2}^{{y}}…
Question Number 117482 by Don08q last updated on 12/Oct/20 $$\:\mathrm{If}\:\:\mathrm{cosec}^{−\mathrm{1}} {x}\:\:=\:\:\mathrm{cot}^{−\mathrm{1}} {y},\:\mathrm{show}\:\mathrm{that} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:\:+\:\:\frac{\mathrm{1}}{{y}^{\mathrm{3}} }\:\:=\:\:\mathrm{0} \\ $$ Answered by TANMAY PANACEA last updated…
Question Number 117470 by TANMAY PANACEA last updated on 11/Oct/20 $$\frac{{d}}{{dx}}{sin}^{−\mathrm{1}} \left(\frac{\mathrm{2}{x}}{\mathrm{1}+{x}^{\mathrm{2}} }\right)\:{atx}=\mathrm{1} \\ $$ Commented by TANMAY PANACEA last updated on 12/Oct/20 $${thank}\:{you}\:{sir} \\…
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Question Number 117344 by bemath last updated on 11/Oct/20 Commented by bemath last updated on 11/Oct/20 $$\mathrm{yes}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{think}\:\mathrm{this}\:\mathrm{question} \\ $$$$\mathrm{wrong} \\ $$ Commented by bemath last…
Question Number 117341 by bemath last updated on 11/Oct/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 117280 by mnjuly1970 last updated on 10/Oct/20 $$\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\:{advanced}\:\:{calculus}…\: \\ $$$$ \\ $$$$\:\:\:\:\:\:{prove}\:\:{that}:: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\mathrm{1}} {ln}\left(\Gamma\left({x}\right)\right).{cos}^{\mathrm{2}} \left(\pi{x}\right){dx} \\ $$$$…