Question Number 112754 by mnjuly1970 last updated on 09/Sep/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 112740 by Mr.D.N. last updated on 09/Sep/20 $$\:\mathrm{Solve}\:\mathrm{differential}\:\mathrm{equation}\:\mathrm{the}\:\mathrm{method}\:\mathrm{of} \\ $$$$\:\mathrm{variation}\:\mathrm{of}\:\mathrm{parameters}: \\ $$$$\:\:\frac{\boldsymbol{\mathrm{d}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{dx}}^{\mathrm{2}} }\:+\mathrm{4}\boldsymbol{\mathrm{y}}\:=\mathrm{4}\:\boldsymbol{\mathrm{cosec}}\:\mathrm{2}\boldsymbol{\mathrm{x}}\: \\ $$ Answered by mathmax by abdo last updated…
Question Number 112720 by deepak@7237 last updated on 09/Sep/20 $$\boldsymbol{\mathrm{Q}}.\:\boldsymbol{{y}}\:=\:\left(\boldsymbol{{x}\mathrm{cos}{x}}\right)^{\boldsymbol{{x}}} +\:\left(\boldsymbol{{x}\mathrm{sin}{x}}\right)^{\frac{\mathrm{1}}{\boldsymbol{{x}}}} \:\boldsymbol{\mathrm{then}}\:\boldsymbol{\mathrm{find}}\:\:\frac{\boldsymbol{{dy}}}{\boldsymbol{{dx}}} \\ $$ Answered by deepak@7237 last updated on 09/Sep/20 Answered by 1549442205PVT last…
Question Number 112714 by deepak@7237 last updated on 09/Sep/20 $$\boldsymbol{\mathrm{Q}}.\:\:\boldsymbol{{y}}\:=\:\boldsymbol{\mathrm{sin}}^{−\mathrm{1}} \left(\frac{\boldsymbol{{a}}\:+\:\boldsymbol{{b}\mathrm{cos}{x}}}{\boldsymbol{{b}}\:+\:\boldsymbol{{a}\mathrm{cos}{x}}}\right)\:,\:\:\boldsymbol{\mathrm{then}}\:\boldsymbol{\mathrm{find}}\:\frac{\boldsymbol{{dy}}}{\boldsymbol{{dx}}} \\ $$ Answered by deepak@7237 last updated on 09/Sep/20 Commented by deepak@7237 last updated…
Question Number 178250 by zaheen last updated on 14/Oct/22 $${how}\:{is}\:{the}\:{solution}\:{of}\:{this}\:{qustion} \\ $$$${f}\left({x}\right)={x}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)\left({x}−\mathrm{3}\right)\left({x}−\mathrm{4}\right)\centerdot…….\centerdot\left({x}−\mathrm{100}\right) \\ $$$${f}^{'} \left({x}\right)=?\:\:\:\:\:\:\:\:\:\:{f}'\left(\mathrm{1}\right)=? \\ $$$$\:\: \\ $$ Answered by CElcedricjunior last updated on…
Question Number 112697 by mnjuly1970 last updated on 09/Sep/20 $$\:\:\:\:\:….{calculus}… \\ $$$${please}\:\:{prove}\:: \\ $$$$ \\ $$$$\:\:\:\:\Omega=\int_{\mathrm{0}} ^{\:\infty} \:\frac{\mathrm{1}}{\left(\mathrm{1}+{x}^{\varphi} \right)^{\varphi} }{dx}\:=\mathrm{1} \\ $$$$\:\varphi::\:\:{golden}\:\:{ratio}\:… \\ $$ Commented…
Question Number 178052 by mnjuly1970 last updated on 12/Oct/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 178051 by mnjuly1970 last updated on 12/Oct/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 112494 by bemath last updated on 08/Sep/20 $$\:\mathrm{y}\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\:\mathrm{dx}\:+\:\mathrm{x}\sqrt{\mathrm{1}+\mathrm{y}^{\mathrm{2}} }\:\mathrm{dy}\:=\:\mathrm{0} \\ $$ Answered by ajfour last updated on 08/Sep/20 $$\frac{\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{{x}^{\mathrm{2}} }{d}\left({x}^{\mathrm{2}} \right)+\frac{\sqrt{\mathrm{1}+{y}^{\mathrm{2}}…
Question Number 46907 by Raj Singh last updated on 02/Nov/18 Answered by ajfour last updated on 02/Nov/18 $${y}=\left({x}^{\mathrm{2}} +\mathrm{3}\right)\left({x}^{\mathrm{3}} −\mathrm{5}\right) \\ $$$${y}+\bigtriangleup{y}=\left[\left({x}+\bigtriangleup{x}\right)^{\mathrm{2}} +\mathrm{3}\right]\left[\left({x}+\bigtriangleup{x}\right)^{\mathrm{3}} −\mathrm{5}\right] \\…