Question Number 45456 by peter frank last updated on 13/Oct/18 Commented by peter frank last updated on 13/Oct/18 $$\mathrm{math1967} \\ $$ Commented by math1967 last…
Question Number 45281 by peter frank last updated on 11/Oct/18 Commented by math1967 last updated on 11/Oct/18 $${pls}\:{chq}.\:{q}.{no}\mathrm{1} \\ $$ Commented by peter frank last…
Question Number 45280 by peter frank last updated on 11/Oct/18 $$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{simultaneous}}\:\boldsymbol{\mathrm{equation}} \\ $$$$\left.\boldsymbol{\mathrm{a}}\right)\boldsymbol{\mathrm{sin}}\left(\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}\right)=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:\:\:} \\ $$$$\boldsymbol{\mathrm{cos}}\mathrm{2}\boldsymbol{\mathrm{x}}=\frac{-\mathrm{1}\:\:}{\mathrm{2}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{ranging}}\:\boldsymbol{\mathrm{from}}\:\mathrm{0}\:\boldsymbol{\mathrm{to}}\:\mathrm{360}\:\boldsymbol{\mathrm{inclusive}} \\ $$$$\left.\boldsymbol{\mathrm{b}}\right)\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{siny}}+\boldsymbol{\mathrm{cosx}}=\boldsymbol{\mathrm{x}}\:\:\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}}\:\frac{\boldsymbol{\mathrm{d}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{dx}}^{\mathrm{2}\:} }\:=\frac{\boldsymbol{\mathrm{x}}}{\left(\mathrm{2}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} \right)^{\frac{\mathrm{3}}{\mathrm{2}}} } \\ $$ Answered by…
Question Number 176274 by mnjuly1970 last updated on 15/Sep/22 Answered by Frix last updated on 16/Sep/22 $${y}=\mathrm{coth}\:{x}\:\Leftrightarrow\:{x}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\frac{{y}+\mathrm{1}}{{y}−\mathrm{1}} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\mathrm{coth}^{−\mathrm{1}} \:\sqrt{\mathrm{2}}\:=\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\mathrm{ln}\:\left(\mathrm{1}+\sqrt{\mathrm{2}}\right) \\ $$$$\underset{\mathrm{0}} {\overset{\pi} {\int}}\frac{\mathrm{sin}^{\mathrm{2}} \:{x}}{\:\sqrt{\mathrm{tan}^{\mathrm{2}}…
Question Number 175952 by cortano1 last updated on 10/Sep/22 $$\:\mathrm{If}\:\mathrm{f}\left(\mathrm{x}\right)=\:\mathrm{csc}\:\left(\frac{\pi\mathrm{x}}{\mathrm{3}}\right)+\mathrm{sec}\:\left(\frac{\pi\mathrm{x}}{\mathrm{6}}\right) \\ $$$$\:\mathrm{and}\:\mathrm{f}\:'\left(\mathrm{a}\right)=\:−\frac{\pi}{\mathrm{9}}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value} \\ $$$$\mathrm{of}\:\mathrm{a}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 175879 by cortano1 last updated on 08/Sep/22 $$\:\:\mathrm{If}\:\mathrm{cos}\:\mathrm{x}\:.\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{y}\:\Rightarrow\mathrm{y}\left(\frac{\pi}{\mathrm{3}}\right)=? \\ $$ Commented by mr W last updated on 08/Sep/22 $$\frac{{dy}}{{y}}=\frac{{dx}}{\mathrm{cos}\:{x}} \\ $$$$\frac{{dy}}{{y}}=\frac{\mathrm{cos}\:{x}\:{dx}}{\mathrm{cos}^{\mathrm{2}} \:{x}} \\…
Question Number 44613 by tio_fernida03 last updated on 02/Oct/18 Commented by ajfour last updated on 02/Oct/18 $${no}\:{minimum}\:{nor}\:{maximum} \\ $$$${since}\:{for}\:{x}=\:−\mathrm{1}.\mathrm{42173},−\mathrm{0}.\mathrm{34566} \\ $$$${denominator}\:{of}\:{h}\left({x}\right)=\mathrm{0}. \\ $$ Terms of…
Question Number 175638 by mnjuly1970 last updated on 04/Sep/22 $$\:\Omega\:=\:\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} \frac{\:\:{sin}\left(\:\mathrm{3}{x}\:\right)}{\:\sqrt{\:\mathrm{1}−\:{sin}\left({x}\right).{cos}\left({x}\right)}}\:{dx}\:=\:\mathrm{2}\left(\sqrt{\:{a}}\:.{ln}\left(\:\mathrm{1}\:+\:\sqrt{{b}\:}\:\:\right)\:+\:{c}\:\right) \\ $$$$ \\ $$$${find}\:{the}\:{value}\:{of}\::\:\:\:\:\:\:{a}\:+\:{b}\:+\:{c}\:=\:?\:\:\:\:\:\:\:\:\:\:\blacksquare\:{m}.{n} \\ $$$$\: \\ $$ Terms of Service Privacy Policy…
Question Number 44557 by ajfour last updated on 01/Oct/18 Commented by ajfour last updated on 01/Oct/18 Commented by ajfour last updated on 01/Oct/18 $${let}\:{P}\:\left({x}_{\mathrm{1}} ,\:{y}_{\mathrm{1}}…
Question Number 175623 by cortano1 last updated on 04/Sep/22 $$\:\mathrm{min}\:\mathrm{f}\left(\mathrm{x}\right)=\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{2x}+\mathrm{5}}\:+\sqrt{\mathrm{4x}^{\mathrm{2}} −\mathrm{4x}+\mathrm{10}} \\ $$ Answered by greougoury555 last updated on 04/Sep/22 $$\:{let}\:\begin{cases}{{a}=\left(\mathrm{1}−{x}\right){i}+\mathrm{2}{j}}\\{{b}=\left(\mathrm{2}{x}−\mathrm{1}\right){i}+\mathrm{3}{j}}\end{cases} \\ $$$$\:\mid{a}\mid\:+\mid{b}\:\mid\:\geqslant\:\mid{a}\:+{b}\mid \\…