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Category: Differentiation

Q-by-using-fourier-series-prove-that-n-1-1-n-1-2n-1-3-3-32-

Question Number 174766 by mnjuly1970 last updated on 10/Aug/22 $$ \\ $$$$\:\:\:\:{Q}:\:\:{by}\:{using}\:{fourier}\:{series}, \\ $$$$\:\:\:\:\:\:{prove}\:\:{that}\:: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\Omega}=\underset{\boldsymbol{{n}}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\:\boldsymbol{{n}}−\mathrm{1}} }{\left(\mathrm{2}\boldsymbol{{n}}−\mathrm{1}\:\right)^{\:\mathrm{3}} }\:=\:\frac{\boldsymbol{\pi}^{\:\mathrm{3}} }{\mathrm{32}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:−−−−−− \\ $$…

Question-43438

Question Number 43438 by peter frank last updated on 10/Sep/18 Answered by tanmay.chaudhury50@gmail.com last updated on 10/Sep/18 $${cosh}^{−} \left(\mathrm{3}{x}\right)={ln}\left(\mathrm{3}{x}+\sqrt{\mathrm{9}{x}^{\mathrm{2}} −\mathrm{1}}\:\right) \\ $$$${y}=\left\{{ln}\left(\mathrm{3}{x}+\sqrt{\mathrm{9}{x}^{\mathrm{2}} −\mathrm{1}}\:\right)\right\}^{\mathrm{2}} \\ $$$$\frac{{dy}}{{dx}}=\mathrm{2}\left\{{ln}\left(\mathrm{3}{x}+\sqrt{\mathrm{9}{x}^{\mathrm{2}}…

Question-174442

Question Number 174442 by oustmuchiya@gmail.com last updated on 01/Aug/22 Answered by floor(10²Eta[1]) last updated on 01/Aug/22 $$\left.\mathrm{a}\right)\: \\ $$$$\mathrm{y}'=\frac{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{4}} }{\mathrm{2}\sqrt{\mathrm{x}−\mathrm{1}}}+\mathrm{4}\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} \sqrt{\mathrm{x}−\mathrm{1}} \\ $$$$\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} \left[\frac{\mathrm{x}+\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{x}−\mathrm{1}}}+\mathrm{4}\sqrt{\mathrm{x}−\mathrm{1}}\right] \\…

Question-108727

Question Number 108727 by Don08q last updated on 18/Aug/20 Answered by Dwaipayan Shikari last updated on 18/Aug/20 $${x}\left({t}\right)={t}^{\mathrm{3}} −\mathrm{15}{t}^{\mathrm{2}} +\mathrm{72}{t}+\mathrm{3} \\ $$$${v}_{{avg}} =\frac{{x}\left(\mathrm{8}\right)−{x}\left(\mathrm{0}\right)}{\mathrm{8}}=\frac{\mathrm{512}−\mathrm{15}.\mathrm{64}+\mathrm{72}.\mathrm{8}+\mathrm{3}−\mathrm{3}}{\mathrm{8}}=\mathrm{16}\frac{{m}}{{s}} \\ $$$$…