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Category: Differentiation

x-6-64-4-2x-1-x-2-x-2-4-4x-1-x-2-4x-2-2x-1-1-2x-dx-

Question Number 171926 by Mikenice last updated on 21/Jun/22 $$\int\:\left(\frac{{x}^{−\mathrm{6}} −\mathrm{64}}{\mathrm{4}+\mathrm{2}{x}^{−\mathrm{1}} +{x}^{−\mathrm{2}} }.\frac{{x}^{\mathrm{2}} }{\mathrm{4}−\mathrm{4}{x}^{−\mathrm{1}} +{x}^{−\mathrm{2}} }\:−\:\frac{\mathrm{4}{x}^{\mathrm{2}} \left(\mathrm{2}{x}+\mathrm{1}\right)}{\mathrm{1}−\mathrm{2}{x}}\right){dx} \\ $$ Commented by infinityaction last updated on…

The-function-f-x-ax-2-bx-c-has-gradient-function-4x-2-and-stationary-value-1-Find-the-values-of-a-b-and-c-

Question Number 171883 by pete last updated on 21/Jun/22 $$\mathrm{The}\:\mathrm{function}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{ax}^{\mathrm{2}} +\mathrm{bx}+\mathrm{c}\:\mathrm{has}\:\mathrm{gradient} \\ $$$$\mathrm{function}\:\mathrm{4x}+\mathrm{2}\:\mathrm{and}\:\mathrm{stationary}\:\mathrm{value}\:\mathrm{1}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:{a},{b}\:\mathrm{and}\:{c}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

let-f-x-ln-1-arctanx-1-calculate-f-n-x-then-f-n-0-2-developp-f-at-integr-serie-

Question Number 40782 by math khazana by abdo last updated on 27/Jul/18 $${let}\:{f}\left({x}\right)={ln}\left(\mathrm{1}+{arctanx}\right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right)\:{then}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie}\:. \\ $$ Terms of Service Privacy…

The-curve-for-which-dy-dx-a-x-p-x-q-where-a-p-and-q-are-constants-has-turning-points-at-2-0-and-1-1-i-state-the-value-of-p-and-q-ii-using-these-values-determine-the-value-of-a-

Question Number 171762 by pete last updated on 20/Jun/22 $$\mathrm{The}\:\mathrm{curve}\:\mathrm{for}\:\mathrm{which}\:\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{a}\left(\mathrm{x}−\mathrm{p}\right)\left(\mathrm{x}−\mathrm{q}\right), \\ $$$$\mathrm{where}\:\mathrm{a},\:\mathrm{p}\:\mathrm{and}\:\mathrm{q}\:\mathrm{are}\:\mathrm{constants},\:\mathrm{has}\:\mathrm{turning} \\ $$$$\mathrm{points}\:\mathrm{at}\:\left(\mathrm{2},\mathrm{0}\right)\:\mathrm{and}\:\left(\mathrm{1},\mathrm{1}\right). \\ $$$$\left.\mathrm{i}\right)\:\mathrm{state}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{p}\:\mathrm{and}\:\mathrm{q}. \\ $$$$\left.\mathrm{ii}\right)\:\mathrm{using}\:\mathrm{these}\:\mathrm{values},\:\mathrm{determine}\:\mathrm{the}\:\mathrm{value} \\ $$$$\mathrm{of}\:{a} \\ $$ Answered by mr…

Question-40479

Question Number 40479 by Raj Singh last updated on 22/Jul/18 Answered by MJS last updated on 22/Jul/18 $${a}=\mathrm{8}+\mathrm{2}{x} \\ $$$${b}={c}={d}=\mathrm{8} \\ $$$${h}=\sqrt{\mathrm{64}−{x}^{\mathrm{2}} } \\ $$$${A}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{2}}\left({a}+{c}\right){h}=\left(\mathrm{8}+{x}\right)\sqrt{\mathrm{64}−{x}^{\mathrm{2}}…