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Category: Differentiation

f-x-3x-5-2x-1-f-x-

Question Number 198953 by ArifinTanjung last updated on 26/Oct/23 $$\mathrm{f}\left(\mathrm{x}\right)=\:\frac{\mathrm{3x}−\mathrm{5}}{\mathrm{2x}+\mathrm{1}}\:\rightarrow\mathrm{f}^{'} \left(\mathrm{x}\right)=….? \\ $$ Answered by Rasheed.Sindhi last updated on 26/Oct/23 $$\mathrm{f}\left(\mathrm{x}\right)=\:\frac{\mathrm{3x}−\mathrm{5}}{\mathrm{2x}+\mathrm{1}}\:\rightarrow\mathrm{f}^{'} \left(\mathrm{x}\right)=….? \\ $$$$\left(\frac{{u}}{{v}}\right)^{'} =\frac{{v}\:{u}'−{u}\:{v}'}{{v}^{\mathrm{2}}…

Question-198988

Question Number 198988 by Safojon last updated on 26/Oct/23 Answered by witcher3 last updated on 26/Oct/23 $$\mathrm{f}\left(\mathrm{x}\right)−\mathrm{g}\left(\mathrm{x}\right)=\mathrm{x}\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{1010}} {\sum}}\left(\mathrm{x}^{\mathrm{2k}} \right)>\mathrm{0} \\ $$$$\mathrm{u}_{\mathrm{n}} =\mathrm{f}^{\left(\mathrm{n}\right)} \left(\frac{\mathrm{1}}{\mathrm{2023}}\right),\mathrm{v}_{\mathrm{n}} =\mathrm{g}^{\left(\mathrm{n}\right)}…

f-tan-x-2f-cot-x-4x-f-x-

Question Number 198562 by cortano12 last updated on 22/Oct/23 $$\:\:\:\mathrm{f}\left(\mathrm{tan}\:\mathrm{x}\right)+\:\mathrm{2f}\left(\mathrm{cot}\:\mathrm{x}\right)\:=\:\mathrm{4x}\: \\ $$$$\:\:\:\mathrm{f}\:'\left(\mathrm{x}\right)=\:? \\ $$ Answered by dimentri last updated on 22/Oct/23 $$\:{let}\:{x}=\frac{\pi}{\mathrm{2}}−{t}\: \\ $$$$\:{f}\left(\mathrm{cot}\:{t}\right)\:+\mathrm{2}\:{f}\left(\mathrm{tan}\:{t}\right)=\:\mathrm{2}\pi−\mathrm{4}{t} \\…

If-f-x-x-1-x-lnt-t-2-1-arctan-t-dt-Prove-that-x-gt-0-f-x-pi-8-pi-0-arctan-1-2-x-1-x-sint-dt-lim-x-f-x-pi-3-16-

Question Number 197384 by Erico last updated on 15/Sep/23 $$\mathrm{If}\:{f}\left({x}\right)=\underset{\:\frac{\mathrm{1}}{\mathrm{x}}} {\int}^{\:\:\mathrm{x}} \frac{{lnt}}{{t}^{\mathrm{2}} −\mathrm{1}}{arctan}\left({t}\right){dt} \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\bullet\:\forall{x}>\mathrm{0}\:\:\:\:\:\:\:\:{f}\left({x}\right)=\:\frac{\pi}{\mathrm{8}}\:\underset{\:\mathrm{0}} {\int}^{\:\pi} \mathrm{arctan}\left[\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{x}−\frac{\mathrm{1}}{\mathrm{x}}\right)\mathrm{sint}\right]\mathrm{dt} \\ $$$$\bullet\underset{\mathrm{x}\rightarrow+\infty} {\mathrm{lim}}\:{f}\left({x}\right)=\frac{\pi^{\mathrm{3}} }{\mathrm{16}} \\ $$…

if-x-cos-u-y-sin-u-and-z-f-x-y-then-show-that-2-z-x-2-2-z-y-2-u-4-2-z-u-2-u-3-z-u-u-4-2-z-2-

Question Number 197317 by universe last updated on 13/Sep/23 $$\:\mathrm{if}\:\:\:\mathrm{x}\:\:=\:\:\frac{\mathrm{cos}\:\theta}{\mathrm{u}}\:\:,\:\mathrm{y}\:\:=\:\frac{\mathrm{sin}\:\theta}{\mathrm{u}}\:\:{and}\:\mathrm{z}\:\:=\:\:\mathrm{f}\left(\mathrm{x},\mathrm{y}\right) \\ $$$$\mathrm{then}\:\mathrm{show}\:\mathrm{that}\: \\ $$$$\:\:\:\frac{\partial^{\mathrm{2}} \mathrm{z}}{\partial\mathrm{x}^{\mathrm{2}} }\:+\:\frac{\partial^{\mathrm{2}} \mathrm{z}}{\partial\mathrm{y}^{\mathrm{2}} }\:=\:\mathrm{u}^{\mathrm{4}} \:\frac{\partial^{\mathrm{2}} \mathrm{z}}{\partial\mathrm{u}^{\mathrm{2}} }\:+\:\mathrm{u}^{\mathrm{3}} \:\frac{\partial\mathrm{z}}{\partial\mathrm{u}}\:+\:\mathrm{u}^{\mathrm{4}} \:\frac{\partial^{\mathrm{2}} \mathrm{z}}{\partial\theta^{\mathrm{2}} }…