Question Number 38455 by maxmathsup by imad last updated on 25/Jun/18 $${solve}\:{the}\:{d}.{e}\:\:{y}^{'} \:−{xe}^{−\mathrm{2}{x}} {y}\:={cos}\left(\mathrm{3}{x}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 169526 by ali009 last updated on 01/May/22 $${solve}\:{the}\:{D}.{E}. \\ $$$${y}^{'} ={tan}\left({x}+{y}\right)−\mathrm{1} \\ $$ Answered by mr W last updated on 01/May/22 $${let}\:{u}={x}+{y} \\…
Question Number 103870 by Ar Brandon last updated on 17/Jul/20 $$\mathcal{D}\acute {\mathrm{e}montrer}\:\mathrm{que}\:\mathrm{la}\:\mathrm{fonction}\: \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{2}} \centerdot\mathrm{sin}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:\mathrm{admet}\:\mathrm{un}\:\mathrm{DL}\:\mathrm{d}'\mathrm{ordre}\:\mathrm{2}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 103835 by mohammad17 last updated on 17/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 103828 by ~blr237~ last updated on 17/Jul/20 $$\:\:\:\:\:{min}\left\{\:\int_{\mathrm{0}} ^{\mathrm{1}} \left({x}^{\mathrm{3}} −{px}−{q}\right)^{\mathrm{2}} {dx}\:,\:\:\left({p},{q}\right)\in\mathbb{R}^{\mathrm{2}} \:\right\} \\ $$ Answered by bobhans last updated on 17/Jul/20 $$\left({x}^{\mathrm{3}}…
Question Number 103820 by ~blr237~ last updated on 17/Jul/20 $$\:\:\:\int_{\mathbb{R}} ^{} \:\frac{{e}^{−\mathrm{2}{i}\pi{ax}} }{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{\mathrm{2}} }{dx}\:=\:\pi{e}^{−\mathrm{2}\pi{a}} \left(\frac{\mathrm{1}}{\mathrm{2}}+\pi{a}\right)\:\:\:\:\:\:\:\:\:{a}>\mathrm{0} \\ $$ Answered by mathmax by abdo last updated…
Question Number 38232 by rahul 19 last updated on 23/Jun/18 $$\mathrm{Differentiate}\: \\ $$$$\mathrm{tan}^{−\mathrm{1}} \left(\frac{\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }−\mathrm{1}}{{x}}\right)\:\: \\ $$$${without}\:{using}\:{any}\:{trigonometric}\: \\ $$$${substitution}\:! \\ $$ Commented by math khazana…
Question Number 38181 by rahul 19 last updated on 22/Jun/18 $$\mathrm{If}\:\mathrm{y}=\:\:{x}^{\left({lnx}\right)^{{ln}\left({lnx}\right)} } \:{then}\:\frac{{dy}}{{dx}}\:=\:? \\ $$ Commented by rahul 19 last updated on 22/Jun/18 $$\mathrm{I}\:'\mathrm{ve}\:\mathrm{done}\:\mathrm{by}\:\mathrm{taking}\:\mathrm{log}\:\mathrm{and}\:\mathrm{I}'\mathrm{m}\:\mathrm{getting} \\…
Question Number 169210 by mnjuly1970 last updated on 26/Apr/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 38092 by ajfour last updated on 21/Jun/18 Commented by ajfour last updated on 22/Jun/18 $${The}\:{circle}\:{touches}\:{x}=\mathrm{0}\:,\:{y}=\mathrm{0}\:, \\ $$$${and}\:{the}\:{ellipse}\:\:\:\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1}\:,\:{in}\:{the} \\ $$$${manner}\:{shown};\:{find}\:{its}\:{radius}\:{R}…