Question Number 168348 by mnjuly1970 last updated on 08/Apr/22 Answered by mathman1234 last updated on 09/Apr/22 $$\mathrm{plz}\:\mathrm{help} \\ $$$$\mathrm{if}\:\mathrm{0}<\mathrm{a}<\mathrm{b}\:\mathrm{and}\:\mathrm{x}>\mathrm{0}\:\mathrm{proove}\:\mathrm{that} \\ $$$$\frac{\mathrm{2}}{\pi}\left(\mathrm{1}−\frac{\mathrm{a}}{\mathrm{b}}\right)\leqslant\mathrm{sup}\mid\frac{\mathrm{sin}\left(\mathrm{ax}\right)}{\mathrm{ax}}\:−\:\frac{\mathrm{sin}\left(\mathrm{ax}\right)}{\mathrm{ax}}\mid\leqslant\mathrm{4}\left(\mathrm{1}−\frac{\mathrm{a}}{\mathrm{b}}\right) \\ $$ Commented by…
Question Number 102813 by bramlex last updated on 11/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 102804 by bramlex last updated on 11/Jul/20 $$\mathrm{The}\:\mathrm{coordinates}\:\mathrm{of}\:\mathrm{two}\:\mathrm{points}\:\mathrm{A} \\ $$$$\&\:\mathrm{B}\:\mathrm{are}\:\left(\mathrm{0},\mathrm{8}\right)\:\mathrm{and}\:\left(\mathrm{9},\mathrm{4}\right) \\ $$$$\mathrm{respectively}.\:\mathrm{The}\:\mathrm{point}\:\mathrm{P}\:\mathrm{with} \\ $$$$\mathrm{coordinate}\:\left(\mathrm{p},\mathrm{0}\right)\:\mathrm{lies}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{x}−\mathrm{axis}\:\mathrm{where}\:\mathrm{0}<\mathrm{p}<\mathrm{9}.\:\mathrm{Let}\:\mathrm{s} \\ $$$$\mathrm{denotes}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of} \\ $$$$\mathrm{two}\:\mathrm{segments}\:\mathrm{PA}\:\mathrm{and}\:\mathrm{PB}\:.\:\mathrm{by} \\ $$$$\mathrm{expressing}\:\mathrm{s}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{p} \\…
Question Number 168244 by mnjuly1970 last updated on 07/Apr/22 Answered by MJS_new last updated on 07/Apr/22 $${x}\geqslant\mathrm{0} \\ $$$$\mathrm{rhs}\:\mathrm{is}\:\mathrm{integer}\:\Rightarrow\:\mathrm{lhs}\:\mathrm{must}\:\mathrm{be}\:\mathrm{integer} \\ $$$${x}^{\mathrm{2}} \geqslant\mathrm{0}\:\Rightarrow\:\lfloor\sqrt{{x}}\rfloor^{\mathrm{2}} +\mathrm{2}\lfloor\sqrt{{x}}\rfloor\geqslant\mathrm{2}\:\Rightarrow\:{x}\geqslant\mathrm{1} \\ $$$$\mathrm{the}\:\mathrm{only}\:\mathrm{solution}\:\mathrm{is}\:{x}=\mathrm{1}…
Question Number 102653 by Sontsaronald last updated on 10/Jul/20 Answered by bemath last updated on 10/Jul/20 $${y}'−{y}\mathrm{tan}\:{x}=\mathrm{sin}\:{x} \\ $$$${IF}\:{u}\left({x}\right)={e}^{−\int{tan}\:{x}\:{dx}\:} \:= \\ $$$${e}^{\mathrm{ln}\left(\mathrm{cos}{x}\right)} =\mathrm{cos}\:{x} \\ $$$${y}\left({x}\right)=\frac{\int\mathrm{cos}\:{x}\mathrm{sin}\:{x}\:{dx}\:+{C}}{\mathrm{cos}\:{x}}…
Question Number 36947 by maxmathsup by imad last updated on 07/Jun/18 $${integrate}\:{the}\:{d}.{equation}\:\:{xy}^{'} \:+{y}\:=\:\frac{\mathrm{2}{x}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{4}} }}\:. \\ $$ Commented by abdo.msup.com last updated on 07/Jun/18 $${h}.{e}\rightarrow\:{xy}^{'} \:+{y}\:=\mathrm{0}\:\Rightarrow\frac{{y}^{'}…
Question Number 102461 by bemath last updated on 09/Jul/20 $$\int\:\frac{{dx}}{\:\sqrt{\mathrm{5}{e}^{\mathrm{2}{x}} +\mathrm{4}{e}^{{x}} +\mathrm{1}}}\:=? \\ $$ Answered by PRITHWISH SEN 2 last updated on 09/Jul/20 $$\int\frac{\mathrm{dx}}{\mathrm{e}^{\mathrm{x}} \sqrt{\frac{\mathrm{1}}{\mathrm{e}^{\mathrm{2x}}…
Question Number 102444 by bemath last updated on 09/Jul/20 $${find}\:{the}\:{area}\:{bounded}\:{the} \\ $$$${curves}\:{y}^{\mathrm{2}} =\:\mathrm{36}+\mathrm{12}{x}\:{and}\: \\ $$$${y}^{\mathrm{2}} =\mathrm{16}−\mathrm{8}{x}\: \\ $$ Answered by bemath last updated on 09/Jul/20…
Question Number 36907 by prof Abdo imad last updated on 07/Jun/18 $${let}\:\:{f}\left({x}\right)=\:\:\frac{\mathrm{1}}{{cosx}}\:\:{find}\:{f}^{\left({n}\right)} \left({x}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 36872 by tanmay.chaudhury50@gmail.com last updated on 06/Jun/18 Terms of Service Privacy Policy Contact: info@tinkutara.com