Question Number 99562 by MamunSarker last updated on 21/Jun/20 Answered by abdomathmax last updated on 21/Jun/20 $$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{sinx}^{\mathrm{cosx}} \:+\mathrm{cosx}^{\mathrm{sinx}} \:\Rightarrow \\ $$$$\mathrm{f}\left(\mathrm{x}\right)\:=\mathrm{e}^{\mathrm{cosxln}\left(\mathrm{sinx}\right)} \:+\mathrm{e}^{\mathrm{sinxln}\left(\mathrm{cosx}\right)} \:\Rightarrow \\ $$$$\mathrm{f}^{'}…
Question Number 33977 by abdo imad last updated on 28/Apr/18 $${find}\:{a}\:{polynome}\:{solution}\:{of}\:{the}\:{diifferencial} \\ $$$${equation}\:{y}^{''} \:+{y}\:={x}^{\mathrm{12}} \:\:. \\ $$ Answered by MJS last updated on 28/Apr/18 $${y}''+{y}={x}^{\mathrm{2}{n}}…
Question Number 165018 by Mathematification last updated on 25/Jan/22 $${y}\:=\:\Gamma\left({m}+{n}\right)\: \\ $$$${Find}\:\frac{{dy}}{{dn}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 99357 by bobhans last updated on 20/Jun/20 $$\mathrm{x}^{\mathrm{2}} +\mathrm{xy}\:+\mathrm{y}^{\mathrm{2}} −\mathrm{3y}\:=\:\mathrm{10}\:,\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\frac{\mathrm{dy}}{\mathrm{dx}}\:\mathrm{at}\:\mathrm{x}=\:\mathrm{2}\: \\ $$ Commented by bemath last updated on 20/Jun/20 $$\mathrm{x}=\mathrm{2}\:\Rightarrow\mathrm{4}+\mathrm{2y}+\mathrm{y}^{\mathrm{2}} −\mathrm{3y}−\mathrm{10}=\mathrm{0}…
Question Number 99260 by Ar Brandon last updated on 19/Jun/20 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation}\: \\ $$$$\mathrm{xy}'−\mathrm{y}+\frac{\mathrm{2x}+\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }=\mathrm{0} \\ $$ Answered by Mr.D.N. last updated on 19/Jun/20 Commented by…
Question Number 164747 by mathlove last updated on 21/Jan/22 $${faind}\:\:\frac{{dy}}{{dx}} \\ $$$${sin}^{−\mathrm{1}} \left({xy}\right)={csc}^{−\mathrm{1}} \left({x}−{y}\right) \\ $$ Answered by mahdipoor last updated on 21/Jan/22 $${sin}^{−\mathrm{1}} \left({xy}\right)={sin}^{−\mathrm{1}}…
Question Number 33676 by NECx last updated on 21/Apr/18 $${How}\:{fast}\:{is}\:{the}\:{height}\:{of}\:{a}\:{balloon} \\ $$$${changing}\:{when}\:\mathrm{500}{m}\:{away}\:{at}\:{an} \\ $$$${angle}\:{of}\:\pi/\mathrm{4}\:{rad}\:{and}\:{the}\:{angle}\:{is} \\ $$$${increasing}\:{by}\:\mathrm{0}.\mathrm{2}{rad}/{min} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 164716 by cortano1 last updated on 21/Jan/22 $$\:\:\:{find}\:{minimum}\:{value}\:{of}\: \\ $$$$\:{f}\left({x}\right)=\mathrm{4sin}\:\mathrm{2}{x}−\mathrm{5sin}\:{x}−\mathrm{5cos}\:{x}+\mathrm{6} \\ $$ Answered by bobhans last updated on 21/Jan/22 $$\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{4cos}\:\left(\frac{\pi}{\mathrm{2}}−\mathrm{2x}\right)−\mathrm{5}\sqrt{\mathrm{2}}\:\mathrm{cos}\:\left(\frac{\pi}{\mathrm{4}}−\mathrm{x}\right)+\mathrm{6} \\ $$$$\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{4cos}\:\mathrm{2}\left(\frac{\pi}{\mathrm{4}}−\mathrm{x}\right)−\mathrm{5}\sqrt{\mathrm{2}}\:\mathrm{cos}\:\left(\frac{\pi}{\mathrm{4}}−\mathrm{x}\right)+\mathrm{6} \\…
Question Number 164671 by mnjuly1970 last updated on 20/Jan/22 $$ \\ $$$$\:\:\:\:\:\:\:\:{solve}\: \\ $$$$\:\:\:\:\:\:{cos}^{\:\mathrm{3}} \left({x}\right)\:+\:{sin}^{\:\mathrm{2}} \left({x}\right)\:=\:\frac{\mathrm{7}}{\mathrm{8}}\: \\ $$$$\:\:\:\:\:\:\:\:\:{adopted}\:{from}\:{youtube}\:… \\ $$$$ \\ $$ Commented by MJS_new…
Question Number 164653 by mnjuly1970 last updated on 20/Jan/22 $$ \\ $$$$\:\:\:\:\:\:\:\:{solve} \\ $$$$\:\:\boldsymbol{\phi}\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \:\frac{\mathrm{ln}^{\:\mathrm{2}} \left(\:{x}\:\right).\:{tanh}^{\:−\mathrm{1}} \left(\:{x}\:\:\right)}{{x}}{dx}\:=? \\ $$$$\:\:\:\Omega=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:\left({tanh}^{−\mathrm{1}} \left({x}\right)\right)^{\:\mathrm{2}} }{\mathrm{1}+{x}}\:=\:? \\…