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Category: Differentiation

m-1-n-1-1-n-1-m-2-n-mn-2-

Question Number 195952 by mnjuly1970 last updated on 13/Aug/23 $$ \\ $$$$\:\:\:\:\Omega\:=\:\underset{{m}=\mathrm{1}} {\overset{\infty} {\sum}}\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\:{n}+\mathrm{1}} }{{m}^{\mathrm{2}} {n}\:+\:{mn}^{\:\mathrm{2}} }\:\:=\:?\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:−−−−− \\ $$ Answered by…

dy-dx-1-y-2-1-x-2-0-

Question Number 195885 by cortano12 last updated on 12/Aug/23 $$\:\:\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:+\:\sqrt{\frac{\mathrm{1}−\mathrm{y}^{\mathrm{2}} }{\mathrm{1}−\mathrm{x}^{\mathrm{2}} }}\:=\:\mathrm{0}\: \\ $$ Answered by mokys last updated on 12/Aug/23 $$\frac{{dy}}{\:\sqrt{\mathrm{1}−{y}^{\mathrm{2}} }}\:+\:\frac{{dx}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:=\:{d}\left(\mathrm{0}\right) \\…

1-f-x-sinx-pi-2-lt-x-2pi-cosx-0-x-pi-2-then-find-the-f-pi-2-2-f-x-sinx-pi-2-lt-x-2pi-cosx-0-x-pi-2-then-find

Question Number 195180 by mustafazaheen last updated on 26/Jul/23 $$ \\ $$$$\mathrm{1}.\:\:\:\:\mathrm{f}\left(\mathrm{x}\right)=\begin{cases}{\mathrm{sinx}\:\:\:\:\:\:,\:\:\:\:\frac{\pi}{\mathrm{2}}<\mathrm{x}\leqslant\mathrm{2}\pi}\\{\mathrm{cosx}\:\:\:\:\:\:,\:\:\:\:\:\mathrm{0}\leqslant\mathrm{x}\leqslant\frac{\pi}{\mathrm{2}}}\end{cases} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{f}^{'} \left(\frac{\pi}{\mathrm{2}}\right)\:=? \\ $$$$\mathrm{2}.\:\:\:\:\:\mathrm{f}\left(\mathrm{x}\right)=\begin{cases}{\mathrm{sinx}\:\:\:\:\:\:,\:\:\:\:\frac{\pi}{\mathrm{2}}<\mathrm{x}\leqslant\mathrm{2}\pi}\\{\mathrm{cosx}\:\:\:\:\:\:,\:\:\:\:\:\mathrm{0}\leqslant\mathrm{x}\leqslant\frac{\pi}{\mathrm{2}}}\end{cases} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{f}'\left(\mathrm{2}\pi\right)\:=? \\ $$$$ \\ $$ Answered by…

f-x-arctan-4sinx-3-5cosx-then-f-pi-3-

Question Number 195137 by mathlove last updated on 25/Jul/23 $${f}\left({x}\right)={arctan}\left(\frac{\mathrm{4}{sinx}}{\mathrm{3}+\mathrm{5}{cosx}}\right)\:\:\:{then}\:{f}^{'} \left(\frac{\pi}{\mathrm{3}}\right)=? \\ $$ Answered by Tokugami last updated on 02/Sep/23 $${f}'\left({x}\right)=\frac{\mathrm{1}}{\mathrm{1}+\left(\frac{\mathrm{4sin}\:{x}}{\mathrm{3}+\mathrm{5cos}\:{x}}\right)^{\mathrm{2}} }\:\frac{{d}}{{dx}}\left(\frac{\mathrm{4sin}\:{x}}{\mathrm{3}+\mathrm{5cos}\:{x}}\right) \\ $$$$=\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{16sin}^{\mathrm{2}} {x}}{\left(\mathrm{3}+\mathrm{5cos}\:{x}\right)^{\mathrm{2}}…

f-x-x-7-2x-1-x-2-x-2-7x-4-x-lt-1-f-1-

Question Number 195170 by mathlove last updated on 25/Jul/23 $${f}\left({x}\right)=\begin{cases}{{x}^{\mathrm{7}} +\mathrm{2}{x}+\mathrm{1}\:\:\:\:\:\:\:;{x}\geqslant\mathrm{2}}\\{{x}^{\mathrm{2}} +\mathrm{7}{x}+\mathrm{4}\:\:\:\:\:\:\:\:;{x}<\mathrm{1}}\end{cases} \\ $$$${f}^{'} \left(\mathrm{1}\right)=? \\ $$ Answered by MM42 last updated on 25/Jul/23 $${f}\left(\mathrm{1}\right)\:,\:{not}\:{available}\:{so}…

Question-194467

Question Number 194467 by horsebrand11 last updated on 08/Jul/23 $$\:\:\:\underline{\downdownarrows} \\ $$ Answered by mr W last updated on 08/Jul/23 $${f}\left({x}\right)=\sqrt{\mathrm{4}^{\mathrm{2}} −\left({x}−\mathrm{4}\right)^{\mathrm{2}} }−\sqrt{\mathrm{1}^{\mathrm{2}} −\left({x}−\mathrm{7}\right)^{\mathrm{2}} }…

X-

Question Number 194325 by horsebrand11 last updated on 03/Jul/23 $$\:\:\cancel{\mathcal{X}} \\ $$ Answered by AST last updated on 04/Jul/23 $$\sqrt[{\mathrm{4}_{} }]{\frac{{x}^{\mathrm{4}} +{y}^{\mathrm{4}} +{z}^{\mathrm{4}} }{\mathrm{3}}}\geqslant\sqrt{\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}}…