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Category: Differentiation

A-gas-expands-according-to-the-law-pv-constant-where-p-is-the-pressure-and-v-is-the-volume-of-the-gas-Initially-v-1000m-3-and-p-40N-m-2-If-the-pressure-is-decreased-at-the-rate-of-5Nm-2-min-1-

Question Number 32316 by NECx last updated on 23/Mar/18 $${A}\:{gas}\:{expands}\:{according}\:{to}\:{the} \\ $$$${law}\:{pv}={constant},{where}\:{p}\:{is}\:{the} \\ $$$${pressure}\:{and}\:{v}\:{is}\:{the}\:{volume}\:{of} \\ $$$${the}\:{gas}.{Initially},{v}=\mathrm{1000}{m}^{\mathrm{3}} \:{and} \\ $$$${p}=\mathrm{40}{N}/{m}^{\mathrm{2}} .{If}\:{the}\:{pressure}\:{is} \\ $$$${decreased}\:{at}\:{the}\:{rate}\:{of}\:\mathrm{5}{Nm}^{−\mathrm{2}} {min}^{−\mathrm{1}} \\ $$$${find}\:{the}\:{rate}\:{at}\:{which}\:{the}\:{gas}\:{is}…

Question-32308

Question Number 32308 by Ruchinna1 last updated on 22/Mar/18 Answered by Joel578 last updated on 23/Mar/18 $$\left(\mathrm{3}\right) \\ $$$${y}''''\:=\:\mathrm{5}{x} \\ $$$$\:{y}'''\:=\:\frac{\mathrm{5}}{\mathrm{2}}{x}^{\mathrm{2}} \:+\:{C} \\ $$$$\:\:{y}''\:=\:\frac{\mathrm{5}}{\mathrm{6}}{x}^{\mathrm{3}} \:+\:{C}_{\mathrm{1}}…

Question-163367

Question Number 163367 by poeter last updated on 06/Jan/22 Answered by som(math1967) last updated on 06/Jan/22 $$\mathrm{1}.\:{equn}\:{of}\:{circle}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{10}\:\left({given}\right) \\ $$$$\:\:\frac{{dy}}{{dx}}=\frac{−{x}}{{y}} \\ $$$$\left[\frac{{dy}}{{dx}}\right]_{\mathrm{1},\mathrm{3}} =\frac{−\mathrm{1}}{\mathrm{3}} \\…