Question Number 30497 by abdo imad last updated on 22/Feb/18 $${integrate}\:\:\mathrm{2}{xy}^{'} \:−{y}\:=\frac{\mathrm{2}}{\mathrm{3}}\:{x}^{\frac{\mathrm{3}}{\mathrm{2}}} \:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30479 by abdo imad last updated on 22/Feb/18 $${integrate}\:\:{y}^{''} \:−\mathrm{2}{y}^{'} \:+{y}\:={t}\:\:{with}\:{y}\left(\mathrm{0}\right)=\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 96012 by mhmd last updated on 29/May/20 Commented by john santu last updated on 29/May/20 $$\left({y}−\sqrt{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} }\right){dx}\:=\:{x}\:{dy}\: \\ $$$$\frac{{dy}}{{dx}}\:=\:\frac{{y}−\sqrt{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} }}{{x}}\:=\:\frac{{y}}{{x}}−\sqrt{\mathrm{1}−\left(\frac{{y}}{{x}}\right)^{\mathrm{2}} }…
Question Number 30428 by abdo imad last updated on 22/Feb/18 $${integrate}\:\:\left(\mathrm{1}+{t}^{\mathrm{2}} \right){y}^{'} ={ty}\:+\mathrm{1}+{t}^{\mathrm{2}} . \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30429 by NECx last updated on 22/Feb/18 $${What}\:{are}\:{the}\:{conditions}\:{for}\:{using} \\ $$$${L}'{hospital}\:{rule}? \\ $$ Commented by prof Abdo imad last updated on 22/Feb/18 $${if}\:{f}\:{and}\:{g}\:{are}\:{n}\:{derivable}\:{at}\:{point}\:{x}_{\mathrm{0}} \:{with}…
Question Number 30421 by abdo imad last updated on 22/Feb/18 $${integrate}\:{y}^{'} −\mathrm{2}{ty}\:+{ty}^{\mathrm{2}} =\mathrm{0} \\ $$ Answered by sma3l2996 last updated on 24/Feb/18 $${y}'={t}\left(\mathrm{2}{y}−{y}^{\mathrm{2}} \right) \\…
Question Number 30422 by abdo imad last updated on 22/Feb/18 $${integrate}\:{the}\:{d}.{e}.\:{y}^{'} \:\mathrm{2}{ty}=\:{sint} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30419 by abdo imad last updated on 22/Feb/18 $${integrate}\:\left(\mathrm{1}+{x}^{\mathrm{2}} \right){y}^{'} \:+{xy}\:−\mathrm{2}{x}=\mathrm{0}\:{with}\:{cond}.{y}\left(\mathrm{1}\right)=\mathrm{0} \\ $$ Answered by sma3l2996 last updated on 24/Feb/18 $$\left(\mathrm{1}+{x}^{\mathrm{2}} \right){y}'={x}\left(\mathrm{2}−{y}\right) \\…
Question Number 30420 by abdo imad last updated on 22/Feb/18 $${integrate}\:{y}^{''} =\:\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{1}+\left({y}^{'} \right)^{\mathrm{2}} }\:\:\:\:\:. \\ $$ Answered by sma3l2996 last updated on 24/Feb/18 $$\frac{{dy}'}{{dx}}=\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{1}+\left({y}'\right)^{\mathrm{2}} }…
Question Number 30417 by abdo imad last updated on 22/Feb/18 $${integrate}\:{the}\:{d}.{e}.\:\:\:\left(\mathrm{1}+{x}^{\mathrm{2}} \right){y}^{'} \:−\mathrm{2}{x}\:{y}\:=\:{e}^{−{x}^{\mathrm{2}} } . \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com