Category: Differentiation

Question Number 96012 by mhmd last updated on 29/May/20 Commented by john santu last updated on 29/May/20 $$\left({y}−\sqrt{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} }\right){dx}\:=\:{x}\:{dy}\: \\ $$$$\frac{{dy}}{{dx}}\:=\:\frac{{y}−\sqrt{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} }}{{x}}\:=\:\frac{{y}}{{x}}−\sqrt{\mathrm{1}−\left(\frac{{y}}{{x}}\right)^{\mathrm{2}} }…

Question Number 30429 by NECx last updated on 22/Feb/18 $${What}\:{are}\:{the}\:{conditions}\:{for}\:{using} \\ $$$${L}'{hospital}\:{rule}? \\ $$ Commented by prof Abdo imad last updated on 22/Feb/18 $${if}\:{f}\:{and}\:{g}\:{are}\:{n}\:{derivable}\:{at}\:{point}\:{x}_{\mathrm{0}} \:{with}…

Question Number 30422 by abdo imad last updated on 22/Feb/18 $${integrate}\:{the}\:{d}.{e}.\:{y}^{'} \:\mathrm{2}{ty}=\:{sint} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 30420 by abdo imad last updated on 22/Feb/18 $${integrate}\:{y}^{''} =\:\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{1}+\left({y}^{'} \right)^{\mathrm{2}} }\:\:\:\:\:. \\ $$ Answered by sma3l2996 last updated on 24/Feb/18 $$\frac{{dy}'}{{dx}}=\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{1}+\left({y}'\right)^{\mathrm{2}} }…

Question Number 30418 by abdo imad last updated on 22/Feb/18 $${integrate}\:{y}^{'} \:−\mathrm{2}{xy}\:=\:{sinx}\:{e}^{{x}^{\mathrm{2}} } \:{with}\:{y}\left(\mathrm{0}\right)=\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com