Question Number 211691 by efronzo1 last updated on 16/Sep/24 Answered by golsendro last updated on 16/Sep/24 $$\:\:\cancel{\underbrace{\boldsymbol{\mathrm{M}}}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 211603 by MrGaster last updated on 14/Sep/24 $$\mathrm{1}.\mathrm{Given}\:\mathrm{a}\:\mathrm{regular}\:\mathrm{tetrahedron}\:\boldsymbol{{ABCD}} \\ $$$$\mathrm{with}\:\mathrm{vertices}\:\boldsymbol{{A}}\left(\mathrm{0},\mathrm{0},\mathrm{0}\right)\boldsymbol{{B}}\left(\boldsymbol{{a}},\mathrm{0},\mathrm{0}\right), \\ $$$$\boldsymbol{{C}}\left(\mathrm{0},\boldsymbol{{a}},\mathrm{0}\right),\boldsymbol{\mathrm{and}}\:\boldsymbol{{D}}\left(\mathrm{0},\mathrm{0},\boldsymbol{{a}}\right).\mathrm{Calculate}\:\mathrm{the} \\ $$$$\:\mathrm{volume}\:\boldsymbol{{V}}\:\:\mathrm{and}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{area}\:\boldsymbol{{S}}\:\boldsymbol{\mathrm{of}} \\ $$$$\mathrm{this}\:\mathrm{tetrahedron}. \\ $$ Answered by BHOOPENDRA last updated…
Question Number 211537 by cherokeesay last updated on 12/Sep/24 Answered by mr W last updated on 12/Sep/24 $$\sqrt{\left({R}−\mathrm{2}\right)^{\mathrm{2}} −\mathrm{2}^{\mathrm{2}} }−\mathrm{2}=\sqrt{{R}^{\mathrm{2}} −\mathrm{6}^{\mathrm{2}} } \\ $$$$\sqrt{{R}^{\mathrm{2}} −\mathrm{4}{R}}=\mathrm{2}+\sqrt{{R}^{\mathrm{2}}…
Question Number 211340 by Tawa11 last updated on 06/Sep/24 Commented by Frix last updated on 06/Sep/24 $$\mathrm{Question}\:\mathrm{211294} \\ $$ Answered by mr W last updated…
Question Number 211323 by mr W last updated on 06/Sep/24 Commented by mr W last updated on 06/Sep/24 $${both}\:{circles}\:{are}\:{concentric}. \\ $$$${find}\:\angle{C}=? \\ $$ Answered by…
Question Number 211277 by mr W last updated on 04/Sep/24 Commented by mr W last updated on 04/Sep/24 $${find}\:{the}\:{volume}\:{of}\:{the}\:{tetrahedron} \\ $$$${in}\:{terms}\:{of}\:{a},{b},{c},\:\theta\:{with}\:\mathrm{0}<\theta\leqslant\mathrm{120}°. \\ $$ Commented by…
Question Number 211265 by Pinto last updated on 03/Sep/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 211235 by behi834171 last updated on 01/Sep/24 Commented by behi834171 last updated on 01/Sep/24 $$\angle\boldsymbol{{ABC}};\:{is}\:{given}. \\ $$$$\boldsymbol{{D}};{is}\:{a}\:{point}\:{as}\:{it}\:{showen},{and} \\ $$$$\boldsymbol{{DG}}\:\:\&\:\boldsymbol{{DF}};\:{are}\:{distance}\:{of}:\boldsymbol{{D}},\:{from}: \\ $$$$\boldsymbol{{AB}}\:\&\:\boldsymbol{{BC}},{such}\:{that}:\frac{\boldsymbol{{DG}}}{\boldsymbol{{DF}}}=\boldsymbol{{k}}\left(\boldsymbol{{constant}}\right) \\ $$$$\boldsymbol{{find}}\:\:\boldsymbol{{the}}\:\:\boldsymbol{{locus}}\:\boldsymbol{{of}}:\:\boldsymbol{{D}}\:.…
Question Number 211188 by Ari last updated on 30/Aug/24 Answered by mr W last updated on 30/Aug/24 $${AB}={x} \\ $$$${BC}={y} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{12}^{\mathrm{2}} \\…
Question Number 211167 by cherokeesay last updated on 30/Aug/24 Commented by Frix last updated on 30/Aug/24 $$\mathrm{12} \\ $$ Answered by som(math1967) last updated on…