Question Number 222830 by Tawa11 last updated on 08/Jul/25 Answered by Frix last updated on 08/Jul/25 $$\underset{{i}=\mathrm{1}} {\overset{{k}} {\sum}}…= \\ $$$$=\frac{\mathrm{32}}{\mathrm{9}}\underset{{i}=\mathrm{1}} {\overset{{k}} {\sum}}\frac{{i}^{\mathrm{3}} }{{k}^{\mathrm{4}} }+\mathrm{120}\underset{{i}=\mathrm{1}}…
Question Number 222753 by mr W last updated on 06/Jul/25 Answered by A5T last updated on 07/Jul/25 $$\mathrm{Let}\:\theta\:\mathrm{be}\:\mathrm{the}\:\mathrm{base}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{any}\:\mathrm{of}\:\mathrm{the}\:\mathrm{isosceles}\:\bigtriangleup \\ $$$$\mathrm{180}−\mathrm{2}\theta+\mathrm{180}−\left(\mathrm{2}\left(\mathrm{180}−\theta−?\right)\right)+\mathrm{90}=\mathrm{180} \\ $$$$\Rightarrow\mathrm{2}?=\mathrm{90}\Rightarrow?=\mathrm{45}° \\ $$ Commented…
Question Number 222684 by alvan545 last updated on 05/Jul/25 Commented by alvan545 last updated on 05/Jul/25 Answered by mr W last updated on 05/Jul/25 Commented…
Question Number 222718 by Mingma last updated on 05/Jul/25 Commented by gabthemathguy25 last updated on 06/Jul/25 $${what}? \\ $$ Commented by AntonCWX8 last updated on…
Question Number 222703 by gabthemathguy25 last updated on 05/Jul/25 Commented by gabthemathguy25 last updated on 06/Jul/25 $${Where}\:{the}\:{circles}\:{radius}\:{is}\:{R}\:=\:\mathrm{7} \\ $$ Answered by mr W last updated…
Question Number 222673 by ajfour last updated on 04/Jul/25 Commented by ajfour last updated on 04/Jul/25 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{Find}\:{small}\:{circle}\:{radius}\:\boldsymbol{{a}}. \\ $$$${Oh}!\:{i}\:{forgot}\:{to}\:{say}\:{almost}-\:{ABCD}\:{is}\:{sq}. \\ $$ Answered by mr W…
Question Number 222646 by Tawa11 last updated on 03/Jul/25 Answered by som(math1967) last updated on 03/Jul/25 $$\:{AB}={BC}−{d},\:{AC}={BC}+{d} \\ $$$$\:\:{AC}^{\mathrm{2}} ={AB}^{\mathrm{2}} +{BC}^{\mathrm{2}} \\ $$$$\left({BC}+{d}\right)^{\mathrm{2}} =\left({BC}−{d}\right)^{\mathrm{2}} +{BC}^{\mathrm{2}}…
Question Number 222659 by Mingma last updated on 03/Jul/25 Answered by mr W last updated on 04/Jul/25 Commented by mr W last updated on 04/Jul/25…
Question Number 222636 by Mingma last updated on 02/Jul/25 Answered by mr W last updated on 04/Jul/25 $${d}=\sqrt{{a}^{\mathrm{2}} −\left({a}−{x}\right)^{\mathrm{2}} }+{x}+\sqrt{{b}^{\mathrm{2}} −\left({b}−{x}\right)^{\mathrm{2}} } \\ $$$$\:\:=\sqrt{\mathrm{2}{ax}−{x}^{\mathrm{2}} }+{x}+\sqrt{\mathrm{2}{bx}−{x}^{\mathrm{2}}…
Question Number 222624 by Lekhraj last updated on 02/Jul/25 Answered by mr W last updated on 02/Jul/25 Commented by mr W last updated on 02/Jul/25…