Category: Geometry

Question Number 187581 by HeferH last updated on 19/Feb/23 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 187549 by Rupesh123 last updated on 18/Feb/23 Answered by HeferH last updated on 18/Feb/23 $$Theheightof△BICistheinradius.$$$$Area=s\cdot I$$$$\frac{\sqrt{s(s-a)(s-b)(s-c)}}{s}=I$$$$s=\frac{7+9+12}{2}=14$$$$\:{I}\:=\:\sqrt{\frac{\left(\mathrm{14}−\mathrm{9}\right)\left(\mathrm{14}−\mathrm{7}\right)\left(\mathrm{14}−\mathrm{12}\right)}{\mathrm{14}}}\:=\:\sqrt{\mathrm{5}}…

Question Number 187524 by sonukgindia last updated on 18/Feb/23 Answered by HeferH last updated on 18/Feb/23 Commented by HeferH last updated on 18/Feb/23 $$\:{Area}\:{of}\:{triangle}\:\left(\sqrt{\mathrm{20}},\sqrt{\mathrm{20}},\sqrt{\mathrm{8}}\right)=\:{A} \…

Question Number 187482 by ajfour last updated on 17/Feb/23 Commented by ajfour last updated on 17/Feb/23 $$If{cone}^{\prime }s\frac{R}{h}=m,greenball$$$$radius=a.Findbtheradiiof$$$$upperballs\left(equal\right),allincontact$$$$thewayshown.$$…

Question Number 187452 by Rupesh123 last updated on 17/Feb/23 Answered by mr W last updated on 17/Feb/23 $$sidelengthofoctagon=a$$$$areaofoctagon{A}_8={(a+2\times \frac{a}{\sqrt{2}})}^2-a^2=2(1+\sqrt{2})a^2$$$${black}\:{area}\:{A}_{{black}}…