Question Number 52433 by Tawa1 last updated on 07/Jan/19 Commented by Tawa1 last updated on 07/Jan/19 $$\mathrm{In}\:\mathrm{the}\:\mathrm{figure},\:\:\:\mathrm{PQRS}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{quadrilateral} \\ $$ Commented by Tawa1 last updated on…
Question Number 52428 by Tawa1 last updated on 07/Jan/19 Commented by Tawa1 last updated on 07/Jan/19 $$\mathrm{In}\:\mathrm{the}\:\mathrm{diagram}\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{inner}\:\mathrm{and}\:\mathrm{outer}\:\mathrm{diameter}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}.\: \\ $$$$ \\ $$$$\mathrm{please}\:\mathrm{help}.\:\:\mathrm{urgent} \\ $$…
Question Number 52426 by ajfour last updated on 07/Jan/19 Commented by ajfour last updated on 07/Jan/19 $${Find}\:\frac{{R}}{{r}}\:\:{if}\:\:\mathrm{sin}\:\theta\:=\:\frac{\mathrm{5}}{\mathrm{13}}\:. \\ $$ Answered by mr W last updated…
Question Number 52409 by ajfour last updated on 07/Jan/19 Commented by ajfour last updated on 07/Jan/19 $$\:\:\:\:{Find}\:\theta\:\left({assuming}\:{no}\:{friction}\right) \\ $$$${specially}\:{if}\:{R}=\mathrm{2}{r}\:\:{and}\:{M}={m}. \\ $$ Answered by mr W…
Question Number 183455 by Acem last updated on 26/Dec/22 Commented by Acem last updated on 26/Dec/22 $$\:{AB}=\:\mathrm{6}.\mathrm{4}\:\:\:\:,\:\:{BC}=\:\mathrm{12}\:\:\:\:,\:\:\:{CD}=\:\mathrm{20}\:\:,\:\:{EF}=\:\mathrm{20} \\ $$$$\:{GH}=\:\mathrm{22} \\ $$$$\:{I},\:{J},\:{K}\:{are}\:{collinear}\:{and}\:{FG}\:{is}\:{wanted} \\ $$$$ \\ $$$$\:{M}\:{X}\:!…
Question Number 183432 by cherokeesay last updated on 25/Dec/22 Commented by Acem last updated on 26/Dec/22 $${Hi}\:{Mr}.\:{Cherok}! \\ $$$$\:{At}\:{first}\:{thank}\:{you}\:{for}\:{this}\:{question},\:{greeting}! \\ $$$$\:{Please},\:{can}\:{you}\:{put}\:{your}\:{solution}\:{in}\:{it}\:{correct} \\ $$$$\:{place}\:{then}\:{remove}\:{this}\:{repeated}\:{question}? \\ $$$$\:\boldsymbol{{As}}\:\boldsymbol{{it}}\:\boldsymbol{{is}}\:\boldsymbol{{not}}\:\boldsymbol{{reasonable}}\:{for}\:{each}\:{person}\:{to}…
Question Number 52360 by ajfour last updated on 06/Jan/19 Commented by ajfour last updated on 06/Jan/19 $${If}\:\theta_{{max}} =\:\mathrm{150}°\:{and}\:\theta_{{min}} =\:\mathrm{75}°\:\:,\:{find} \\ $$$${a}\:{and}\:{b}\:{in}\:{terms}\:{of}\:{radius}\:{R}. \\ $$ Answered by…
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Question Number 183393 by cherokeesay last updated on 25/Dec/22 Answered by mr W last updated on 25/Dec/22 Commented by mr W last updated on 25/Dec/22…
Question Number 183389 by Acem last updated on 25/Dec/22 Answered by HeferH last updated on 25/Dec/22 $$\mathrm{65}°\:=\:{x} \\ $$$$\left.{Merry}\:{xmas}\:{btw}\::\right) \\ $$ Commented by Acem last…